把”0102030405”分成5组('0', '1'), ('0', '2'), ('0', '3'), ('0', '4'), ('0', '5')

re.findall(r"(\d)(\d)",s)

>>> re.findall(r"(\d)(\d)",s)

[('0', '1'), ('0', '2'), ('0', '3'), ('0', '4'), ('0', '5')]

04-30 07:58