HDU.1166 敌兵布阵 (线段树 单点更新 区间查询)

题意分析

加深理解,重写一遍

代码总览

#include <bits/stdc++.h>
#define nmax 100000
using namespace std;
struct Tree{
int l,r,val;
int lazy;
int mid(){
return (l+r)>>1;
}
};
Tree tree[nmax<<2];
int num[nmax<<2];
void PushUp(int rt)
{
tree[rt].val = tree[rt<<1].val + tree[rt<<1|1].val;
}
void Build(int l, int r, int rt)
{
tree[rt].l = l; tree[rt].r = r;
tree[rt].val = tree[rt].lazy = 0;
if(l == r){
tree[rt].val = num[l];
return;
}
Build(l,tree[rt].mid(),rt<<1);
Build(tree[rt].mid()+1,r,rt<<1|1);
PushUp(rt);
}
void UpdatePoint(int val, int pos, int rt)
{
if(tree[rt].l == tree[rt].r){
tree[rt].val+=val;
return;
}
if(pos<= tree[rt].mid()) UpdatePoint(val,pos,rt<<1);
else UpdatePoint(val,pos,rt<<1|1);
PushUp(rt);
}
int Query(int l,int r,int rt)
{
if(l>tree[rt].r || r<tree[rt].l) return 0;
if(l <= tree[rt].l && tree[rt].r <= r) return tree[rt].val;
return Query(l,r,rt<<1) + Query(l,r,rt<<1|1);
}
int T,N,a,b;
char op[10];
int main()
{
//freopen("in.txt","r",stdin);
scanf("%d",&T);
for(int i = 1;i<=T;++i){
printf("Case %d:\n",i);
scanf("%d",&N);
for(int j = 1;j<=N;++j) scanf("%d",&num[j]);
Build(1,N,1);
while(scanf(" %s",op) && op[0] != 'E'){
scanf("%d %d",&a,&b);
if(op[0] == 'Q'){
printf("%d\n",Query(a,b,1));
}else if(op[0] == 'A'){
UpdatePoint(b,a,1);
}else{
UpdatePoint(-b,a,1);
}
} }
return 0;
}
04-30 06:37