ss请cc来家里钓鱼，鱼塘可划分为n＊m的格子，每个格子有不同的概率钓上鱼，cc一直在坐标(x,y)的格子钓鱼，而ss每分钟随机钓一个格子。问t分钟后他们谁至少钓到一条鱼的概率大？为多少？

include "stdafx.h"

#include<iostream>

#include<vector>

#include<math.h>

#include <iomanip>

using namespace std;

int main()

{

	int n,m, x, y, t;

	while (cin>>n>>m>>x>>y>>t)

	{

		vector<vector<float>> pVec;

		for (int i = 0; i < n; i++)

		{

			vector<float>  vec;

			for (int j = 0; j < m ; j++)

			{

				float p;

				cin >> p;

			//	cout << "内层循环" << endl;

				vec.push_back(p);

			}

			pVec.push_back(vec);

		}

		float ccP = 1-pow((1-pVec[x-1][y-1]),(double)t);

float ssP = 0.0;

		int num = 0;

		for (int x = 0; x < n; x++)

		{

			for (int y = 0; y < m; y++)

			{

				ssP = ssP+ pVec[x][y ];

			}

		}

		  ssP = ssP/n/m;

		  ssP = 1 - pow((1 -ssP), (double)t);

		  //设置输出标志

		  ssP = ssP * 100;

		  ccP = ccP * 100;

		  int sp = ssP;

		  int cp = ccP;

		  ssP = sp / 100;

		  ccP = cp / 100;

		  cout << setiosflags(ios::fixed);

			if (ssP >ccP)

			{

				cout << "ss" << endl;

				cout << setprecision(2) << ssP << endl;

			}

			else if (ssP <ccP)

			{

				cout << "cc" << endl;

				cout << setprecision(2) << ccP << endl;

			}

			else

			{

				cout << "equal" << endl;

				cout << setprecision(2)<<ccP << endl;

			}

	}

	return 0;

}