一、问题分析
org.springframework.mail.MailSendException: Failed messages: javax.mail.SendFailedException: Invalid Addresses
分析：可能是收件人或抄送人列表存在无效的地址
二、解决方案
遍历异常，提取无效地址后过滤原地址列表再次发送
1.发邮件方法代码
/**
* 发送html邮件
*
* @param to
* @param cc
* @param subject
* @param content
*/
public void sendHtmlMail(String[] to, String[] cc, String subject, String content) {
MimeMessage message = mailSender.createMimeMessage();
MimeMessageHelper helper = null;
try {
//true表示需要创建一个multipart message
helper = new MimeMessageHelper(message, true);
helper.setFrom(from);
helper.setTo(to);
helper.setCc(cc);
helper.setSubject(subject);
helper.setText(content, true);
mailSender.send(message);
logger.info("sendHtmlMail success.from:" + from);
} catch (Throwable e) {
logger.error("sendHtmlMail fail.", e);
String[] invalid = getInvalidAddresses(e);
if (invalid != null) {
sendHtmlMail(filterByArray(to, invalid), filterByArray(cc, invalid), subject, content);
}
}
}
2.从异常获取无效地址的方法代码
/**
* 从异常获取无效地址
* @param e
* @return
*/
private static String[] getInvalidAddresses(Throwable e) {
if (e == null) {
return null;
}
if (e instanceof MailSendException) {
System.out.println("e instanceof SendFailedException");
Exception[] exceptions = ((MailSendException) e).getMessageExceptions();
for (Exception exception : exceptions) {
if (exception instanceof SendFailedException) {
return getStringAddress(((SendFailedException) exception).getInvalidAddresses());
}
}
}
if (e instanceof SendFailedException) {
return getStringAddress(((SendFailedException) e).getInvalidAddresses());
}
return null;
}
/**
* 将Address[]转成String[]
* @param address
* @return
*/
private static String[] getStringAddress(Address[] address) {
List<String> invalid = new ArrayList<>();
for (Address a : address) {
String aa = ((InternetAddress) a).getAddress();
if (!StringUtils.isEmpty(aa)) {
invalid.add(aa);
}
}
return invalid.stream().distinct().toArray(String[]::new);
}
3.过滤发件人中无效地址的方法代码
/**
* 过滤数组source，规则为数组元素包含了数组filter中的元素则去除
*
* @param source
* @param filter
* @return
*/
private static String[] filterByArray(String[] source, String[] filter) {
List<String> result = new ArrayList<>();
for (String s : source) {
boolean contains = false;
for (String f : filter) {
if (s.contains(f)) {
contains = true;
break;
}
}
if (!contains) {
result.add(s);
}
}
return result.stream().toArray(String[]::new);
}