介绍：FastJson 是ailibaba 的一款解析Json的开源框架
使用方式1
引入jar 包
<dependency>
<groupId>com.alibaba</groupId>
<artifactId>fastjson</artifactId>
<version>1.2.15</version>
</dependency>
@SpringBootApplication
//启动类extends WebMvcConfigurerAdapter
public class App extends WebMvcConfigurerAdapter{
//重写configureMessageConverters
@Override
public void configureMessageConverters(List<HttpMessageConverter<?>> converters) {
super.configureMessageConverters(converters); FastJsonHttpMessageConverter fastConverter = new FastJsonHttpMessageConverter();
FastJsonConfig fastJsonConfig = new FastJsonConfig();
//是否需要格式化
fastJsonConfig.setSerializerFeatures(SerializerFeature.PrettyFormat);
fastConverter.setFastJsonConfig(fastJsonConfig);
converters.add(fastConverter);
} public static void main(String[] args) {
SpringApplication.run(App.class, args);
}
}
使用方式2
@SpringBootApplication
public class App {
//使用@Bean 依赖注入
@Bean
public HttpMessageConverters fastJsonHttpMessageConverters() {
FastJsonHttpMessageConverter fastConverter = new FastJsonHttpMessageConverter();
FastJsonConfig fastJsonConfig = new FastJsonConfig();
fastJsonConfig.setSerializerFeatures(SerializerFeature.PrettyFormat);
fastConverter.setFastJsonConfig(fastJsonConfig);
HttpMessageConverter<?> converter = fastConverter;
return new HttpMessageConverters(converter);
} public static void main(String[] args) {
SpringApplication.run(App.class, args);
}
}
FastJson 其他用法：
格式化：
@JSONField(format = "yyyy-MM-dd")
private Date createDate;
自定义名称：
@JSONField(name = "AGE")
private int age;
将 Java 对象转换换为 JSON 对象：
JSON.toJSONString()
创建JSON 对象：
public void whenGenerateJson_thanGenerationCorrect() throws ParseException {
JSONArray jsonArray = new JSONArray();
for (int i = 0; i < 2; i++) {
JSONObject jsonObject = new JSONObject();
jsonObject.put("AGE", 10);
jsonObject.put("FULL NAME", "Doe " + i);
jsonObject.put("DATE OF BIRTH", "2016/12/12 12:12:12");
jsonArray.add(jsonObject);
}
String jsonOutput = jsonArray.toJSONString();
}JSON 对象需要转java对象：
public void whenJson_thanConvertToObjectCorrect() {
Person person = new Person(20, "John", "Doe", new Date());
String jsonObject = JSON.toJSONString(person);
Person newPerson = JSON.parseObject(jsonObject, Person.class)
}