SQL练习题    
 
 注:查询列表不建议用 “*”
1.列出至少有一个雇员的所有部门;
a.
select * from dept where deptno in(select distinct deptno from emp);
b.
(oracle11gCBO 新特性 in(多个值)会智能过滤掉重复字段,通过执行计划验证);
select * from dept where deptno in (select deptno from emp group by deptno having count(deptno)>=1);
c.
select * from dept a where exists (select null from emp b where a.deptno=b.deptno);
 
2.列出薪金比smith多的所有雇员
select ename from emp where sal>(select sal from emp where ename='SMITH');
 
3.列出雇员的姓名及其直接上级姓名(注:列出执行计划原由于显示结果不同,结果显示第二个执行计划要优秀一点,第一个执行计划走了全表扫描也符合常理,第二个走的唯一索引,索引>堆表;测试表较小没有参考价值仅得出结果不同,有利于以后做查询优化)
a.
select e.ename,p.ename from emp e,emp p where  p.empno(+)=e.mgr;
select p.ename,e.ename from emp p left join emp e on e.empno=p.mgr;

  

执行计划:
Execution Plan
----------------------------------------------------------
Plan hash value: 2341341676 ---------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
---------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 14 | 280 | 7 (15)| 00:00:01 |
|* 1 | HASH JOIN OUTER | | 14 | 280 | 7 (15)| 00:00:01 |
| 2 | TABLE ACCESS FULL| EMP | 14 | 140 | 3 (0)| 00:00:01 |
| 3 | TABLE ACCESS FULL| EMP | 14 | 140 | 3 (0)| 00:00:01 |
--------------------------------------------------------------------------- Predicate Information (identified by operation id):
--------------------------------------------------- 1 - access("E"."EMPNO"(+)="P"."MGR") Statistics
----------------------------------------------------------
1 recursive calls
0 db block gets
15 consistent gets
0 physical reads
0 redo size
823 bytes sent via SQL*Net to client
523 bytes received via SQL*Net from client
2 SQL*Net roundtrips to/from client
0 sorts (memory)
0 sorts (disk)
14 rows processed

  

 
 
b.
select e.ename,(select ename from emp p where  p.empno=e.mgr)as BoosName from emp e;

  

执行计划:
Execution Plan
----------------------------------------------------------
Plan hash value: 4000517069 --------------------------------------------------------------------------------
------ | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time
| --------------------------------------------------------------------------------
------ | 0 | SELECT STATEMENT | | 14 | 140 | 3 (0)| 00:0
0:01 | | 1 | TABLE ACCESS BY INDEX ROWID| EMP | 1 | 10 | 1 (0)| 00:0
0:01 | |* 2 | INDEX UNIQUE SCAN | PK_EMP | 1 | | 0 (0)| 00:0
0:01 | | 3 | TABLE ACCESS FULL | EMP | 14 | 140 | 3 (0)| 00:0
0:01 | --------------------------------------------------------------------------------
------ Predicate Information (identified by operation id):
--------------------------------------------------- 2 - access("P"."EMPNO"=:B1) Statistics
----------------------------------------------------------
1 recursive calls
0 db block gets
17 consistent gets
0 physical reads
0 redo size
849 bytes sent via SQL*Net to client
523 bytes received via SQL*Net from client
2 SQL*Net roundtrips to/from client
0 sorts (memory)
0 sorts (disk)
14 rows processed

  

 
 
 
4.列出入职日期早于其直接上级的所有雇员
a.
select p.ename from emp e,emp p where e.empno=p.mgr and p.hiredate<e.hiredate;

  

b.
select e.ename from emp e where e.hiredate<(select  hiredate from emp p where p.empno=e.mgr);

  

 
5、列出部门名称和这些部门的雇员,同时列出那些没有雇员的部门
a.
select a.dname,b.ename from dept a,emp b where  a.deptno=b.deptno(+);

  

 
b.
select a.dname,b.ename from dept a left join emp b on  a.deptno=b.deptno

  

 
6、列出所有“CLERK”(办事员)的姓名及其部门名称
select b.ename,a.dname from dept a,emp b where  a.deptno=b.deptno and b.job='CLERK';

  

 
7、列出各种工作类别的最低薪金,显示最低薪金大于1500的记录
select min(sal)as minsal,job from emp group by job having  min(sal)>1500;

  

 
--8、列出从事“SALESMAN”(销售)工作的雇员的姓名,假定不知道销售部的部门编号
select ename from emp where deptno=(select deptno from  dept where dname='SALES');

  

 
9、列出薪金高于公司平均水平的所有雇员

select ename from emp where sal>(select avg(sal) from  emp);

  

 
10、列出与“SCOTT”从事相同工作的所有雇员
select ename from emp where job=(select job from emp  where ename='SCOTT');

  

 
11、列出某些雇员的姓名和薪金,条件是他们的薪金等于部门30中任何一个雇员的薪金
select ename,sal from emp where sal in (select sal from  emp where deptno=30);

  

 
12、列出某些雇员的姓名和薪金,条件是他们的薪金高于部门30中所有雇员的薪金
select ename,sal from emp where sal > (select max(sal)  from emp where deptno=30);

  

 
13、列出每个部门的信息以及该部门中雇员的数量
select a.deptno,a.dname,a.loc,b.ss from dept a,(select  deptno,count(ename) ss from emp group by deptno) b
where a.deptno=b.deptno;

  

 
14、列出所有雇员的雇员名称、部门名称和薪金
select a.ename,b.dname,a.sal from emp a,dept b where  a.deptno=b.deptno(+);

  

 
15、列出从事同一种工作但属于不同部门的雇员的不同组合
select a.ename,b.ename,a.job,b.job,a.deptno,b.deptno from  emp a,emp b
where a.job=b.job and a.deptno<>b.deptno;

  

16、列出分配有雇员数量的所有部门的详细信息,即使是分配有0个雇员
a.
select a.deptno,a.dname,a.loc,nvl(b.ss,0) from dept a,
(select deptno,count(ename) ss from emp group by deptno) b where a.deptno=b.deptno(+);

  

b.
select a.deptno,dname,loc,count(empno) ss from dept a,emp  b where a.deptno=b.deptno(+)
group by a.deptno,a.dname,a.loc;

  

 
17、列出各种类别工作的最低工资
select job,min(sal) as minjobsal from emp group by job;

  

 
18、列出各个部门的MANAGER(经理)的最低薪金
select deptno,min(sal) ss from emp where job='MANAGER'  group by deptno;

  

 
19、列出按年薪排序的所有雇员的年薪
select ename,(sal*12+nvl(comm,0)) as nianxin from emp  order by nianxin;

  

20、列出薪金水平处于第四位的雇员
a.
select ename,a.tt from (select rownum  tt,ename,(sal*12+nvl(comm,0)) as nianxin from emp)a where  a.tt=4; 
b.
select * from (select ename,sal,rank()over(order by sal  desc)as nn from emp) where nn=4;
05-11 14:48