Given two strings s and t , write a function to determine if t is an anagram of s.

Example 1:

Input: s = "anagram", t = "nagaram"
Output: true

Example 2:

Input: s = "rat", t = "car"
Output: false

Note:
You may assume the string contains only lowercase alphabets.

Follow up:
What if the inputs contain unicode characters? How would you adapt your solution to such case?

想法:将字符串s和字符串t分别转成容器存储,然后按字符顺序排序。再比较两个容器是否相等。

class Solution {
public:
    bool isAnagram(string s, string t) {
        vector<char> st1;
        vector<char> st2;
         ; i < s.size() ; i++){
            st1.push_back(s.at(i));
        }
        sort(st1.begin(),st1.end());
         ; j < t.size() ; j++){
            st2.push_back(t.at(j));
        }
                          sort(st2.begin(),st2.end());
                          return st1 == st2;
    }
};
05-11 18:08