1147: 零起点学算法54——Fibonacc

Time Limit: 1 Sec Memory Limit: 64 MB 64bit IO Format: %lld
Submitted: 2097 Accepted: 863
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Description

Fibonacci数列定义为（1,1,2,3,5,8,.....），即每个元素是前两个元素的和。如果一个Fibonacci数与所有小于它的Fibonacci数互质，那么称之为Fibonacci质数。

现在要求你输出前n个Fibonacci数
The Fibonacci Numbers {0, 1, 1,
2, 3, 5, 8, 13, 21, 34, 55 ...} are defined by the recurrence:
F(0)=0
F(1)=1
F(i)=F(i-1)+F(i-2)
Write a program to calculate the Fibonacci Numbers.

Input

The first line of the
input file contains a single integer T, the number of test cases. The following
T lines,each contains an integer n ( 0 <= n <= 45 ), and you are expected
to calculate Fn

Output

Output Fn on a
separate line.

Sample Input

Sample Output

Source

零起点学算法

 #include<stdio.h>

 int main(){

     int T,a[]={,,};

     for(int i=;i<=;i++){

         a[i]=a[i-]+a[i-];

     }

     scanf("%d",&T);

     for(int i=;i<T;i++){

         int n;

         scanf("%d",&n);

         printf("%d\n",a[n]);

     }

     return ;

 }