笨办法是，使用一个后台线程，遍历所有对象，挨个检查。
但对象数量过多时，存在性能问题，检查间隔时间不好设置，间隔时间过大，影响精确度，多小则存在效率问题。而且做不到按超时的时间顺序处理。
这场景，使用DelayQueue最适合了。
Delayed 元素的一个无界阻塞队列，只有在延迟期满时才能从中提取元素。
该队列的头部是延迟期满后保存时间最长的Delayed元素（即最想优先处理的元素）。如果延迟都还没有期满，则队列没有头部，并且 poll 将返回 null。
当一个元素的 getDelay(TimeUnit.NANOSECONDS) 方法返回一个小于等于 0 的值时，将发生到期。
即使无法使用take或poll移除未到期的元素，也不会将这些元素作为正常元素对待。例如，size方法同时返回到期和未到期元素的计数。此队列不允许使 null元素。
DelayQueue队列中保存的是实现了Delayed接口的实现类，里面必须实现getDelay()和compareTo()方法。前者用于取DelayQueue里面的元素时判断是否到了延时时间，否则不予获取，是则获取。 compareTo()方法用于进行队列内部的排序。compareTo 方法需提供与 getDelay 方法一致的排序。
DelayQueue = BlockingQueue + PriorityQueue + Delayed
PriorityBlockingQueue = BlockingQueue + PriorityQueue
DelayQueue的关键元素BlockingQueue、PriorityQueue、Delayed。
可以这么说，DelayQueue是一个使用优先队列（PriorityQueue）实现的BlockingQueue，优先队列的比较基准值是时间。通过PriorityQueue，可以优先处理最紧急的元素，利用BlockingQueue，能防止不必要的不断轮询，提高了性能。在很多需要回收对象的场景都能用上。
代码示例
场景一
模拟一个考试的日子，考试时间为120分钟，30分钟后才可交卷，当时间到了，或学生都交完卷了考试结束。主要注意的：
1、考试时间为120分钟，30分钟后才可交卷，初始化考生完成试卷时间最小应为30分钟
2、对于能够在120分钟内交卷的考生，如何实现这些考生交卷
3、对于120分钟内没有完成考试的考生，在120分钟考试时间到后需要让他们强制交卷
4、在所有的考生都交完卷后，需要将控制线程关闭
下面是自己修改了的代码：
package com.bbk.demo;
import java.util.Iterator;
import java.util.Random;
import java.util.concurrent.CountDownLatch;
import java.util.concurrent.DelayQueue;
import java.util.concurrent.Delayed;
import java.util.concurrent.TimeUnit;
/**
* DelayQueue
* @author wasim
* @project Demo
* @create at 2015-10-6 下午4:37:31
*/
public class Exam {
public static void main(String[] args) throws InterruptedException {
int studentNumber = 20;
CountDownLatch countDownLatch = new CountDownLatch(studentNumber+1);
DelayQueue< Student> students = new DelayQueue<Student>();
Random random = new Random();
for (int i = 0; i < studentNumber; i++) {
students.put(new Student("student"+(i+1), 30+random.nextInt(120),countDownLatch));
}
Thread teacherThread =new Thread(new Teacher(students));
students.put(new EndExam(students, 120,countDownLatch,teacherThread));
teacherThread.start();
countDownLatch.await();
System.out.println(" 考试时间到，全部交卷！");
}
}
class Student implements Runnable,Delayed{
private String name;
private long workTime;
private long submitTime;
private boolean isForce = false;
private CountDownLatch countDownLatch;
public Student(){}
public Student(String name,long workTime,CountDownLatch countDownLatch){
this.name = name;
this.workTime = workTime;
//提交时间 = 当前时间 + 作答时间
this.submitTime = TimeUnit.NANOSECONDS.convert(workTime, TimeUnit.NANOSECONDS)+System.nanoTime();
this.countDownLatch = countDownLatch;
}
@Override
public int compareTo(Delayed o) {
// 按照作答时长正序排序（队头放的是你认为最先需要处理的元素，在这里体现为需要最先交卷，所以是正序）
if(o == null || ! (o instanceof Student)) return 1;
if(o == this) return 0;
Student s = (Student)o;
if (this.workTime > s.workTime) {
return 1;
}else if (this.workTime == s.workTime) {
return 0;
}else {
return -1;
}
}
@Override
public long getDelay(TimeUnit unit) {
// 提交时间 - 当前时间 用来判断延迟是否到期（即是否可以提交试卷，可以进行take或者poll）
// 返回正数：延迟还有多少时间到期。负数：延迟已经在多长时间前到期。负数代表可以take或者poll
return unit.convert(submitTime - System.nanoTime(), TimeUnit.NANOSECONDS);
}
@Override
public void run() {
if (isForce) {
System.out.println(name + " 交卷, 希望用时" + workTime + "分钟"+" ,实际用时 120分钟" );
}else {
System.out.println(name + " 交卷, 希望用时" + workTime + "分钟"+" ,实际用时 "+workTime +" 分钟");
}
countDownLatch.countDown();
}
public boolean isForce() {
return isForce;
}
public void setForce(boolean isForce) {
this.isForce = isForce;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public long getWorkTime() {
return workTime;
}
public void setWorkTime(long workTime) {
this.workTime = workTime;
}
public long getSubmitTime() {
return submitTime;
}
public void setSubmitTime(long submitTime) {
this.submitTime = submitTime;
}
}
class EndExam extends Student{
private DelayQueue<Student> students;
private CountDownLatch countDownLatch;
private Thread teacherThread;
public EndExam(DelayQueue<Student> students, long workTime, CountDownLatch countDownLatch,Thread teacherThread) {
super("强制收卷", workTime,countDownLatch);
this.students = students;
this.countDownLatch = countDownLatch;
this.teacherThread = teacherThread;
}
@Override
public void run() {
teacherThread.interrupt();
Student tmpStudent;
for (Iterator<Student> iterator2 = students.iterator(); iterator2.hasNext();) {
tmpStudent = iterator2.next();
tmpStudent.setForce(true);
System.out.println(tmpStudent.getName()+"==="+tmpStudent.getDelay(TimeUnit.NANOSECONDS));
tmpStudent.run();
}
countDownLatch.countDown();
}
}
class Teacher implements Runnable{
private DelayQueue<Student> students;
public Teacher(DelayQueue<Student> students){
this.students = students;
}
@Override
public void run() {
try {
System.out.println(" test start");
while(!Thread.interrupted()){
Student s = students.take();
System.out.println(s.getName()+"==="+s.getDelay(TimeUnit.NANOSECONDS));
s.run();
}
} catch (Exception e) {
e.printStackTrace();
}
}
}
场景二
向缓存添加内容时，给每一个key设定过期时间，系统自动将超过过期时间的key清除。需要注意的是：
1、当向缓存中添加key-value对时，如果这个key在缓存中存在并且还没有过期，需要用这个key对应的新过期时间
2、为了能够让DelayQueue将其已保存的key删除，需要重写实现Delayed接口添加到DelayQueue的DelayedItem的hashCode函数和equals函数
3、当缓存关闭，监控程序也应关闭，因而监控线程应当用守护线程
网上搜到的相关代码：
/**
*Cache.java
*
* Created on 2014-1-11 上午11:30:36 by sunzhenchao [email protected]
*/
public class Cache<K, V> {
public ConcurrentHashMap<K, V> map = new ConcurrentHashMap<K, V>();
public DelayQueue<DelayedItem<K>> queue = new DelayQueue<DelayedItem<K>>();
public void put(K k,V v,long liveTime){
V v2 = map.put(k, v);
DelayedItem<K> tmpItem = new DelayedItem<K>(k, liveTime);
if (v2 != null) {
queue.remove(tmpItem);
}
queue.put(tmpItem);
}
public Cache(){
Thread t = new Thread(){
@Override
public void run(){
dameonCheckOverdueKey();
}
};
t.setDaemon(true);
t.start();
}
public void dameonCheckOverdueKey(){
while (true) {
DelayedItem<K> delayedItem = queue.poll();
if (delayedItem != null) {
map.remove(delayedItem.getT());
System.out.println(System.nanoTime()+" remove "+delayedItem.getT() +" from cache");
}
try {
Thread.sleep(300);
} catch (Exception e) {
// TODO: handle exception
}
}
}
/**
* TODO
* @param args
* 2014-1-11 上午11:30:36
* @author:孙振超
* @throws InterruptedException
*/
public static void main(String[] args) throws InterruptedException {
Random random = new Random();
int cacheNumber = 10;
int liveTime = 0;
Cache<String, Integer> cache = new Cache<String, Integer>();
for (int i = 0; i < cacheNumber; i++) {
liveTime = random.nextInt(3000);
System.out.println(i+" "+liveTime);
cache.put(i+"", i, random.nextInt(liveTime));
if (random.nextInt(cacheNumber) > 7) {
liveTime = random.nextInt(3000);
System.out.println(i+" "+liveTime);
cache.put(i+"", i, random.nextInt(liveTime));
}
}
Thread.sleep(3000);
System.out.println();
}
}
class DelayedItem<T> implements Delayed{
private T t;
private long liveTime ;
private long removeTime;
public DelayedItem(T t,long liveTime){
this.setT(t);
this.liveTime = liveTime;
this.removeTime = TimeUnit.NANOSECONDS.convert(liveTime, TimeUnit.NANOSECONDS) + System.nanoTime();
}
@Override
public int compareTo(Delayed o) {
if (o == null) return 1;
if (o == this) return 0;
if (o instanceof DelayedItem){
DelayedItem<T> tmpDelayedItem = (DelayedItem<T>)o;
if (liveTime > tmpDelayedItem.liveTime ) {
return 1;
}else if (liveTime == tmpDelayedItem.liveTime) {
return 0;
}else {
return -1;
}
}
long diff = getDelay(TimeUnit.NANOSECONDS) - o.getDelay(TimeUnit.NANOSECONDS);
return diff > 0 ? 1:diff == 0? 0:-1;
}
@Override
public long getDelay(TimeUnit unit) {
return unit.convert(removeTime - System.nanoTime(), unit);
}
public T getT() {
return t;
}
public void setT(T t) {
this.t = t;
}
@Override
public int hashCode(){
return t.hashCode();
}
@Override
public boolean equals(Object object){
if (object instanceof DelayedItem) {
return object.hashCode() == hashCode() ?true:false;
}
return false;
}
}