[题目链接]

https://www.lydsy.com/JudgeOnline/problem.php?id=2946

[算法]

建立多串后缀树

对于后缀树上的每个点 , 判断该节点所代表的等价类是否在所以字符串中出现 , 用该点的深度更新答案

时间复杂度 : O(NL)

[代码]

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
const int N = 1e5 + ;
const int ALPHA = ; int n , ans;
char s[N]; template <typename T> inline void chkmax(T &x,T y) { x = max(x,y); }
template <typename T> inline void chkmin(T &x,T y) { x = min(x,y); }
template <typename T> inline void read(T &x)
{
T f = ; x = ;
char c = getchar();
for (; !isdigit(c); c = getchar()) if (c == '-') f = -f;
for (; isdigit(c); c = getchar()) x = (x << ) + (x << ) + c - '';
x *= f;
} struct Suffix_Automaton
{
int sz , last;
int father[N] , child[N][ALPHA] , depth[N];
bool lab[N][];
vector< int > a[N];
Suffix_Automaton()
{
sz = ;
last = ;
}
inline int new_node(int dep)
{
depth[++sz] = dep;
father[sz] = ;
memset(child[sz] , , sizeof(child[sz]));
memset(lab[sz] , , sizeof(lab[sz]));
return sz;
}
inline void extend(int ch , int c)
{
int np = child[last][ch];
if (np)
{
if (depth[np] == depth[last] + )
{
lab[np][c] = true;
last = np;
} else
{
int nq = new_node(depth[last] + );
father[nq] = father[np];
father[np] = nq;
memcpy(child[nq] , child[np] , sizeof(child[nq]));
for (int p = last; child[p][ch] == np; p = father[p])
child[p][ch] = nq;
lab[nq][c] = true;
last = nq;
}
} else
{
int np = new_node(depth[last] + );
int p = last;
while (child[p][ch] == )
{
child[p][ch] = np;
p = father[p];
}
if (child[p][ch] == np)
{
father[np] = ;
lab[np][c] = true;
last = np;
return;
}
int q = child[p][ch];
if (depth[q] == depth[p] + )
{
father[np] = q;
lab[np][c] = true;
last = np;
return;
} else
{
int nq = new_node(depth[p] + );
father[nq] = father[q];
father[np] = father[q] = nq;
memcpy(child[nq] , child[q] , sizeof(child[q]));
while (child[p][ch] == q)
{
child[p][ch] = nq;
p = father[p];
}
lab[np][c] = true;
last = np;
return;
}
}
}
inline void insert(char *s , int col)
{
last = ;
for (int i = ; i <= strlen(s + ); ++i)
extend(s[i] - 'a' , col);
}
inline void dfs(int u)
{
for (unsigned i = ; i < a[u].size(); ++i)
{
int v = a[u][i];
dfs(v);
for (int j = ; j <= n; ++j)
lab[u][j] |= lab[v][j];
}
bool all = true;
for (int i = ; i <= n; ++i) all &= lab[u][i];
if (all) chkmax(ans , depth[u]);
}
inline void work()
{
for (int i = ; i <= sz; ++i)
a[father[i]].push_back(i);
dfs();
}
} SAM; int main()
{ read(n);
for (int i = ; i <= n; ++i)
{
scanf("%s" , s + );
SAM.insert(s , i);
}
SAM.work();
printf("%d\n" , ans); return ; }
05-12 08:49