# 2.写函数，接收n个数字，求这些参数数字的和。（动态传参）
def func1(*args):
sum = 0
for i in args:
sum += i
print(sum)
func1(1,2,3,4,5)
# sum = 0
# def func1(*args):
# for i in args:
# global sum
# sum += i
# print('答案等于',sum)
# # func1(1,2,3,4,5)
# while 1:
# shuzi = int(input('输入数字：'))
# func1(shuzi)
3.读代码，回答：代码中,打印出来的值a,b,c分别是什么？为什么？
a=10
b=20
def test5(a,b):
print(a,b)
c = test5(b,a)
print(c)
a = 10
b = 20
def test5(a, b):
print(a, b)
c = test5(b, a) #b =20 a =10
print(c)'''
#20 10 none
'''
4.读代码，回答：代码中,打印出来的值a,b,c分别是什么？为什么？
a=10
b=20
def test5(a,b):
a=3
b=5
print(a,b)
c = test5(b,a)
print(c)
a=10
b=20
def test5(a,b):
a=3
b=5
print(a,b)
c = test5(b,a) # b =20 a =10
print(c)'''
#3 5 none
'''
5.传入函数中多个列表和字典,如何将每个列表的每个元素
依次添加到函数的动态参数args里面？
如何将每个字典的所有键值对依次添加到kwargs里面？
'''
l1 = [1,2,3]
l2 = ['a','b','c']
l3 = [(1,2),1,{1:3}]
def func5(*args):
print(*args,end=' ')
func5(*l1)
def func6(*args):
print(*args)
for l in args:
func5(*l)
func6(l1,l2,l3)
d1={1:2,3:4}
d2={'a':'b','c':'d'}
func6(d1,d2)
6.下面代码成立么?如果不成立为什么报错?怎么解决?
6.1
a = 2
def wrapper():
print(a)
wrapper()
6.2
a = 2
def wrapper():
a += 1
print(a)
wrapper()
6.3
def wrapper():
a = 1
def inner():
print(a)
inner()
wrapper()
6.4
def wrapper():
a = 1
def inner():
a += 1
print(a)
inner()
wrapper()'''
'''7.写函数,接收两个数字参数,将较小的数字返回.'''
def func7(can1 , can2):
if can1 > can2:
return can2
else:
return can1
# func7(1,2)
print(func7(1,2))
'''8.写函数,接收一个参数(此参数类型必须是可迭代对象),
将可迭代对象的每个元素以’_’相连接,形成新的字符串,并返回.
例如 传入的可迭代对象为[1,'老男孩','武sir']返回的结果为’1_老男孩_武sir’'''
a = [1,'老男孩','武sir']
def func8(*args):
for i in args:
# print(args)
print(i,end='_')
func8(*a)
#从最里层返回任意一个字符串，在最外层打印
def fua(args):
def fub(args):
def fuc(args):
def fud(args):
a = 8
return a
a = fud(0)
return a
a = fuc(0)
return a
a = fub(0)
return a
print(fua(0))