要求:

打不死的小强!

返回一个数组被截断n个元素后还剩余的元素,截断从索引0开始。

结果:

  • slasher([1, 2, 3], 2) 应该返回 [3].
  • slasher([1, 2, 3], 0) 应该返回 [1, 2, 3].
  • slasher([1, 2, 3], 9) 应该返回 []slasher([1, 2, 3], 4) 应该返回 [].
  • slasher(["burgers", "fries", "shake"], 1) 应该返回 ["fries", "shake"].
  • slasher([1, 2, "chicken", 3, "potatoes", "cheese", 4], 5) 应该返回 ["cheese", 4].

代码:

方法一:使用slice()

 //Array.slice()

 function slasher(arr, howMany) {
// it doesn't always pay to be first
var newarr; if(arr.length>howMany){
newarr=arr.slice(howMany);
return newarr;
}else{
newarr=[];
return newarr;
}
//return arr;
} slasher([1, 2, 3], 2);

方法二:使用splice()

 function slasher(arr, howMany) {
// it doesn't always pay to be first
arr.splice(0,howMany); return arr;
}
05-08 14:49