题目链接:http://poj.org/problem?id=1696

题意:给你n个点,然后我们用一条线把它们连起来,形成螺旋状;

首先找到左下方的一个点作为起点,然后以它为原点进行极角排序,找到极角最小的那个点,如果又多个选距离近的,每次都这样循环找n个点即可;

#include <stdio.h>
#include <iostream>
#include <algorithm>
#include <string.h> using namespace std; typedef long long LL; const double eps = 1e-;
const int N = ; struct point
{
int x, y, Id; point(){}
point(int x, int y) : x(x), y(y) {} point operator - (const point &b)const
{
return point(x-b.x, y-b.y);
}
int operator ^ (const point &b)const
{
return x*b.y - b.x*y;
}
}; int dist(point a, point b)
{
return (a.x-b.x)*(a.x-b.x) + (a.y-b.y)*(a.y-b.y);
} int start, n; point p[N]; bool cmp(point a, point b)
{
int k = (a-p[start])^(b-p[start]);
if(k == )
return dist(p[start], a)<dist(p[start], b);
return k>;
} int main()
{
int T; scanf("%d", &T); while(T--)
{
scanf("%d", &n); for(int i=; i<n; i++)
{
scanf("%d %d %d", &p[i].Id, &p[i].x, &p[i].y);
if(p[i].y < p[].y || (p[i].y==p[].y && p[].x>p[i].x))
swap(p[i], p[]);
} start = ; for(int i=; i<n; i++)
{
sort(p+i, p+n, cmp); start ++;
} printf("%d", n); for(int i=; i<n; i++)
printf(" %d", p[i].Id); printf("\n");
}
return ;
}
05-11 20:22