/*
第几天？
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 144001 Accepted Submission(s): 51677
Problem Description
给定一个日期，输出这个日期是该年的第几天。
Input
输入数据有多组，每组占一行，数据格式为YYYY/MM/DD组成，具体参见sample input ,另外，可以向你确保所有的输入数据是合法的。
Output
对于每组输入数据，输出一行，表示该日期是该年的第几天。
Sample Input
1985/1/20
2006/3/12
Sample Output
20
71
*/
#include<stdio.h>
int main(void)
{
int nian = 0,yue = 0,day = 0,T = 0;
while(scanf("%d/%d/%d",&nian,&yue,&day) != EOF)
{
if(yue == 1)
{
printf("%d\n",day);
}
else if(yue <= 2)
{
printf("%d\n",31 + day);
}
else
{
if(nian %4 == 0&&nian % 100 !=0 || nian % 400 == 0)
T = 29;
else
T = 28;
if(yue == 3)
printf("%d\n",31 + T + day);
else if(yue == 4)
printf("%d\n",31*2 + T + day);
else if(yue == 5)
printf("%d\n",31*2 + T + 30 + day);
else if(yue == 6)
printf("%d\n",31*3 + T + 30 + day);
else if(yue == 7)
printf("%d\n",31*3 + T + 30*2 + day);
else if(yue == 8)
printf("%d\n",31*4 + T + 30*2 + day);
else if(yue == 9)
printf("%d\n",31*5 + T + 30*2 + day);
else if(yue == 10)
printf("%d\n",31*5 + T + 30*3 + day);
else if(yue == 11)
printf("%d\n",31*6 + T + 30*3 + day);
else if(yue == 12)
printf("%d\n",31*6 + T + 30*4 + day);
}
}
return 0;
}