将list集合的元素按照添加顺序的倒序进行排列取出

1.方法

Collections.reverse(list);

2.代码示例

/**

     * 从redis中将现场状态的记录全部取出

     * @param aucId

     * @return

     */

    @RequestMapping(value = "/findAllAuctionLocalStatementRecord", method = RequestMethod.POST)

    @ResponseBody

    public List<Object> findAllAuctionLocalStatementRecord(String aucId) {

        if (logger.isDebugEnabled()) {

            logger.debug("findAllAuctionLocalStatementRecord, aucId:{}", aucId);

        }

        List<Object> list = redisTemplateListDTO.opsForValue().get("auctionLocalStatement"+aucId);

        Collections.reverse(list);//将list集合倒序排列取出,时间最新的在最上面

        return list;

    }