Problem Description

  Given n integers.
  You have two operations:
  U A B: replace the Ath number by B. (index counting from 0)
  Q A B: output the length of the longest consecutive increasing subsequence (LCIS) in [a, b].

  题目大意就是给你一个数列,求区间内的最长连续子序列。以及对某一个点的值进行更改。

  线段树维护区间内的LCIS,前缀LCIS,后缀LCIS就可。

代码如下:

#include<iostream>
#include<cstdio>
#include<cstring> #define lson L,M,po*2
#define rson M+1,R,po*2+1
#define lc po*2
#define rc po*2+1 using namespace std; const int maxn=10e5+; int mBIT[maxn*],lBIT[maxn*],rBIT[maxn*];
int num[maxn]; void pushUP(int po,int len,int M)
{
mBIT[po]=max(mBIT[lc],mBIT[rc]);
lBIT[po]=lBIT[lc];
rBIT[po]=rBIT[rc]; if(num[M]<num[M+])
{
mBIT[po]=max(mBIT[po],rBIT[lc]+lBIT[rc]); if(lBIT[lc]==len-(len/))
lBIT[po]+=lBIT[rc]; if(rBIT[rc]==(len/))
rBIT[po]+=rBIT[lc];
}
} void build_tree(int L,int R,int po)
{
if(L==R)
{
scanf("%d",&num[L]);
mBIT[po]=lBIT[po]=rBIT[po]=; return;
} int M=(L+R)/; build_tree(lson);
build_tree(rson); pushUP(po,R-L+,M);
} void update(int up,int L,int R,int po)
{
if(L==R&&L==up)
return; int M=(L+R)/; if(up<=M)
update(up,lson);
else
update(up,rson); pushUP(po,R-L+,M);
} int query(int ql,int qr,int L,int R,int po)
{
if(ql<=L&&qr>=R)
return mBIT[po]; int M=(L+R)/; if(qr<=M)
return query(ql,qr,lson);
if(ql>M)
return query(ql,qr,rson); int ans=max(query(max(ql,L),M,lson),query(M+,min(qr,R),rson));
int temp=min(rBIT[lc],M-ql+)+min(lBIT[rc],qr-M); if(num[M]<num[M+]) //这里要判断!
return max(ans,temp);
else
return ans;
} int main()
{
int N,M;
int a,b;
char c[];
int T;
cin>>T; while(T--)
{
scanf("%d %d",&N,&M); build_tree(,N-,); while(M--)
{
scanf("%s %d %d",c,&a,&b); if(c[]=='Q')
printf("%d\n",query(a,b,,N-,));
else
{
num[a]=b;
update(a,,N-,);
}
}
} return ;
}
05-11 10:48