A1377. 楼房重建

题目：http://www.tsinsen.com/A1377

题解：分块大法好。每块维护一个有序表，修改暴力修改，查询从前往后跳即可。

代码：

 #include<cstdio>

 #include<cstdlib>

 #include<cmath>

 #include<cstring>

 #include<algorithm>

 #include<iostream>

 #include<vector>

 #include<map>

 #include<set>

 #include<queue>

 #include<string>

 #define inf 2000000000

 #define maxn 250000+5

 #define maxm 5005

 #define eps 1e-10

 #define ll long long

 #define ull unsigned long long

 #define pa pair<int,int>

 #define for0(i,n) for(int i=0;i<=(n);i++)

 #define for1(i,n) for(int i=1;i<=(n);i++)

 #define for2(i,x,y) for(int i=(x);i<=(y);i++)

 #define for3(i,x,y) for(int i=(x);i>=(y);i--)

 #define for4(i,x) for(int i=head[x],y=e[i].go;i;i=e[i].next,y=e[i].go)

 #define for5(n,m) for(int i=1;i<=n;i++)for(int j=1;j<=m;j++)

 #define mod 1000000007

 #define lch k<<1,l,mid

 #define rch k<<1|1,mid+1,r

 #define sqr(x) (x)*(x)

 using namespace std;

 inline int read()

 {

     int x=,f=;char ch=getchar();

     while(ch<''||ch>''){if(ch=='-')f=-;ch=getchar();}

     while(ch>=''&&ch<=''){x=*x+ch-'';ch=getchar();}

     return x*f;

 }

 int n,m,l[maxn],r[maxn],b[maxn],s[maxn];

 double a[maxn],c[maxm][maxm];

 int main()

 {

    freopen("input.txt","r",stdin);

    freopen("output.txt","w",stdout);

    n=read();int T=read();m=sqrt(n*log2(n));

    for1(i,n)b[i]=(i-)/m+;

    for1(i,b[n])l[i]=(i-)*m+,r[i]=min(i*m,n),c[i][]=inf;

    while(T--)

    {

         int x=read(),y=read(),t=b[x];

         a[x]=(double)y/(double)x;

         s[t]=;for2(i,l[t],r[t])if(a[i]>c[t][s[t]])c[t][++s[t]]=a[i];

         c[t][s[t]+]=inf;

         double tmp=;int ans=;

      for1(i,b[n])ans+=s[i]-(upper_bound(c[i]+,c[i]+s[i]+,tmp)-c[i])+,tmp=max(tmp,c[i][s[i]]);

      printf("%d\n",ans);

    }

    return ;

 }