题目链接:https://vjudge.net/problem/UVA-315

题目:求割点。

 #include <iostream>
#include <cstdio>
#include <algorithm>
using namespace std; const int N = ;
int n,tim,tot,root = ;
int head[N],dfn[N],low[N],poi[N];
struct node{
int to;
int nxt;
}e[N*N]; void init(){
for(int i = ; i <= n; ++i){
head[i] = -;
dfn[i] = poi[i] = ;
}
tim = tot = ;
} inline void add(int u,int v){
e[tot].to = v;
e[tot].nxt = head[u];
head[u] = tot++;
} void tarjan(int now,int pre){
dfn[now] = low[now] = ++tim;
int to,son = ;
for(int o = head[now]; ~o; o = e[o].nxt){
to = e[o].to;
if(to == pre) continue; //处理无向图的双向边问题
if(!dfn[to]){
++son;
tarjan(to,now);
low[now] = min(low[now],low[to]);
//割点条件1
if(now != root && dfn[now] <= low[to]) poi[now] = ;
}
else if(low[now] > dfn[to]) low[now] = dfn[to];
}
//割点条件2
if(now == root && son >= ) poi[now] = ;
} int main(){ int u,v;
char ch; while(~scanf("%d",&n) && n){
init(); while(~scanf("%d",&u) && u){
while(~scanf("%d%c",&v,&ch)){
add(u,v); add(v,u);
if(ch == '\n') break;
}
}
tarjan(,);
int ans = ;
for(int i = ; i <= n; ++i)
if(poi[i]) ++ans; printf("%d\n",ans);
} return ;
}
05-16 00:04