Atcoder ABC 139B

题意:

解法:

CODE:

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm> using namespace std; #define LL long long
#define N 100010 LL a,b,ans; int main() {
scanf("%lld%lld",&a,&b);
if(b == 1) {
puts("0");
return 0;
}
LL cnt = 1;
while(true) {
cnt = cnt + a - 1;
ans++;
if(cnt >= b) break;
}
printf("%lld",ans);
//system("pause");
return 0;
}
05-20 10:07