题意:

输入中序和后序的权值,输出哪个叶子使它到根的路径上权和最小。

思路:

输入后建树,然后dfs求最小的叶子。

 #include<iostream>
#include<cstdio>
#include<queue>
#include<cstring>
#include<sstream>
using namespace std; int mid[], post[];
int judge[];
struct node {
int index;
node *left, *right;
node()
{
left = right = NULL;
}
};
int n;
bool input(int* a)//输入函数
{
string line;
memset(a, , sizeof(a));
if (!getline(cin, line))
return false;
stringstream ss(line);
int x;
n = ;
while (ss >> x)
a[n++] = x;
//printf("n=%d\n", n);//
return n>;
} int cnt, res;
node* build(node* root, int l, int r)
{
int i;
int t = post[--cnt];
for (i = l; i<r; i++)
{
if (t == mid[i])
break;
}
root = new node();
root->index = t;
/* 注意下面是先建右边然后建左边
因为后序往前走(--cnt) */
if (i<r - )
root->right = build(root->right, i + , r);
if (i>l)
root->left = build(root->left, l, i); return root;
} void preorder(node *root)
{
printf("%d ", root->index);
if (root->left != NULL)
preorder(root->left);
if (root->right != NULL)
preorder(root->right);
}
int best, best_num;
void dfs(node *root, int sum)
{
sum += root->index;
if (!root->left && !root->right)
{
if (best_num>sum || (sum == best_num&&root->index<best))
{
best = root->index;
//printf("best=%d\n", best);
best_num = sum;
}
}
if (root->left != NULL)
dfs(root->left, sum);
if (root->right != NULL)
dfs(root->right, sum);
} int main()
{
while (input(mid))
{
input(post);
cnt = n;
//printf("cnt=%d\n", cnt);
memset(judge, , sizeof(judge));
node *root = NULL;
root = build(root, , n);
best_num = ;
//preorder(root);
//printf("\n");
dfs(root,);
printf("%d\n",best);
}
return ;
}
05-11 13:38