hdu 1228

Description

读入两个小于100的正整数A和B,计算A+B. 
需要注意的是:A和B的每一位数字由对应的英文单词给出. 

 

Input

测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出. 

 

Output

对每个测试用例输出1行,即A+B的值. 

 

Sample Input

one + two =
three four + five six =
zero seven + eight nine =
zero + zero =

 

Sample Output

3
90
96

 

 

考虑好空格和加数的位数就可以了

#include<bits/stdc++.h>

#define one 1

#define two 2

#define three 3

#define four 4

#define five 5

#define six 6

#define seven 7

#define eight 8

#define nine 9

#define zero 0

using namespace std;

    char a[];

    int i=;

    int t=;

    int num[];

    int con=;

    int flag=;

int main()

{

    while(scanf("%c",&a[i])){

        if(a[i]>='a'&&a[i]<='z')

            {

                con++;

                i++;

            }

            else if(a[i]=='+') {i++;flag =t;}

            else if(a[i]!='=')

            {

                if(con==)

                {

                    if(a[i-]=='o'&&a[i-]=='n') num[t++]=;

                    else if(a[i-]=='t'&&a[i-]=='w') num[t++]=;

                    else if(a[i-]=='s') num[t++]=;

                }

                else if(con==)

                {

                    if(a[i-]=='u') num[t++]=;

                    else if(a[i-]=='v') num[t++]=;

                    else if(a[i-]=='n') num[t++]=;

                    else if(a[i-]=='r') num[t++]=;

                }

                else if(con==)

                {

                    if(a[i-]=='e') num[t++]=;

                    else if(a[i-]=='n') num[t++]=;

                    else if(a[i-]=='t') num[t++]=;

                 }

                con=;

                i++;

            }

            else if(a[i]=='=')

            {

                if(num[]==num[]&&num[]==) return ;

                if(t==) cout<<num[]+num[]<<endl;

                else if(t==&&flag==) cout<<num[]*+num[]+num[]<<endl;

                else if(t==&&flag==) cout<<num[]+num[]*+num[]<<endl;

                else cout<<num[]*+num[]+num[]*+num[]<<endl;

                memset(a,NULL,sizeof(a));

                i=;

                con=;

                memset(num,NULL,sizeof(num));

                t=;

                flag=;

            }

        }

    }