【HDU 1228】A + B

题

Description

读入两个小于100的正整数A和B,计算A+B. 
需要注意的是:A和B的每一位数字由对应的英文单词给出. 

 

Input

测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出. 

 

Output

对每个测试用例输出1行,即A+B的值. 

 

Sample Input

one + two =
three four + five six =
zero seven + eight nine =
zero + zero =

 

Sample Output

3
90
96

#include<stdio.h>

#include<string.h>

char str[],letter[][]= {"zero","one","two",

"three","four","five","six","seven","eight","nine"};

int flag,a,b,num;

int main()

{

    while(~scanf("%s",str))

    {

        if(strcmp(str,"="))//不为=

        {

            for(int i=; i<; i++)

                if(!strcmp(letter[i],str))//为数字i

                {

                    num=i;

                    if(!flag) a=a*+num;//+前，统计i

                    else b=b*+num;

                    break;

                }

            if(!strcmp(str,"+")) flag=!flag;//为+

        }

        else

        {

            if(!a&&!b)break;

            printf("%d\n",a+b);

            a=b=;//不要忘记清零

        }

    }

    return ;

}