1.定义

inner join(等值连接) : 仅仅返回两个表中联结字段相等的记录

left join(左联接) :返回包含左表中的全部记录和右表中联结字段相等的记录

right join(右联接) :返回包含右表中的全部记录和左表中联结字段相等的记录

INNER JOIN 语法:

INNER JOIN 连接两个数据表的使用方法:

SELECT * FROM 表1 INNER JOIN 表2 ON 表1.字段号=表2.字段号

2.实例

表A记录例如以下:

aID               a Num   

1                  a20050111

2                  a20050112

3                  a20050113

4                  a20050114

5                  a20050115

表B记录例如以下:

bID               bName

1                   2006032401

2                  2006032402

3                  2006032403

4                  2006032404

8                  2006032408

实验例如以下:

1.left join

sql语句例如以下: 

select * from A

left join B 

on A.aID = B.bID

结果例如以下:

aID               aNum                          bID                  bName

1                   a20050111                1                      2006032401

2                   a20050112                2                     2006032402

3                   a20050113                3                     2006032403

4                   a20050114                4                     2006032404

5                   a20050115                NULL              NULL

(所影响的行数为 5 行)

结果说明:

               left join是以A表的记录为基础的,A能够看成左表,B能够看成右表,left join是以左表为准的.

换句话说,左表(A)的记录将会所有表示出来,而右表(B)仅仅会显示符合搜索条件的记录(样例中为: A.aID = B.bID).

B表记录不足的地方均为NULL.

2.right join

sql语句例如以下: 

select * from A

right join B 

on A.aID = B.bID

结果例如以下:

aID               aNum                          bID                  bName

1                   a20050111                1                      2006032401

2                   a20050112                2                     2006032402

3                   a20050113                3                     2006032403

4                   a20050114                4                     2006032404

NULL           NULL                          8                     2006032408

(所影响的行数为 5 行)

结果说明:

        细致观察一下,就会发现,和left join的结果刚好相反,这次是以右表(B)为基础的,A表不足的地方用NULL填充.

3.inner join

sql语句例如以下: 

select * from A

innerjoin B 

on A.aID = B.bID

结果例如以下:

aID               aNum                          bID                  bName

1                   a20050111                1                      2006032401

2                   a20050112                2                     2006032402

3                   a20050113                3                     2006032403

4                   a20050114                4                     2006032404

结果说明:

        非常明显,这里仅仅显示出了 A.aID = B.bID的记录.这说明inner join并不以谁为基础,它仅仅显示符合条件的记录.  还有就是inner join 能够结合where语句来使用 如:   select * from A innerjoin B on A.aID = B.bID where b.bname='2006032401' 这种话 就仅仅会放回一条数据了

05-08 08:23