USACO Runaround Numbers 模拟

根据题意的 Runaround 规则去找比当前数大的最近的一个 Runaround数字

模拟题~

Source code:

/*

ID: wushuai2

PROG: runround

LANG: C++

*/

//#pragma comment(linker, "/STACK:16777216") //for c++ Compiler

#include <stdio.h>

#include <iostream>

#include <fstream>

#include <cstring>

#include <cmath>

#include <stack>

#include <string>

#include <map>

#include <set>

#include <list>

#include <queue>

#include <vector>

#include <algorithm>

#define Max(a,b) (((a) > (b)) ? (a) : (b))

#define Min(a,b) (((a) < (b)) ? (a) : (b))

#define Abs(x) (((x) > 0) ? (x) : (-(x)))

#define MOD 1000000007

#define pi acos(-1.0)

using namespace std;

typedef long long           ll      ;

typedef unsigned long long  ull     ;

typedef unsigned int        uint    ;

typedef unsigned char       uchar   ;

template<class T> inline void checkmin(T &a,T b){if(a>b) a=b;}

template<class T> inline void checkmax(T &a,T b){if(a<b) a=b;}

const double eps = 1e-      ;

const int M =          ;

const ll P = 10000000097ll   ;

const int INF = 0x3f3f3f3f   ;

const int MAX_N =          ;

const int MAXSIZE = ;

ll num;

ll a[];

void toStr(ll num){

    int i, j, k;

    memset(a, , sizeof(a));

    while(num){

        a[++a[]] = num % 10LL;

        num /= 10LL;

    }

    for(i = ; i <= a[] / ; ++i){

        swap(a[i], a[a[] - i + ]);

    }

}

void toNum(){

    int i, j, k;

    num = ;

    ll nl = 1LL;

    for(i = a[]; i >= ; --i){

        num += nl * a[i];

        nl *= 10LL;

    }

}

bool solve(){

    int i, j, k, pos;

    ll ans[];

    ll cur = a[];

    ll b[], bigg = ;

    bool vis[];

    memset(vis, , sizeof(vis));

    memset(ans, , sizeof(ans));

    for(i = ; i <= a[]; ++i){

        checkmax(bigg, a[i]);

        if(a[i] == )   return false;

        if(ans[a[i]])   return false;

        ans[a[i]] = true;

    }

    for(;;){

        memset(b, , sizeof(b));

        for(pos = ; pos <= a[]; ++pos){

            if(cur == a[pos])   break;

        }

        for(i = pos; i <= cur + pos - ; ++i){

            b[++b[]] = a[i % a[] + ];

        }

        /*

        for(i = 1; i <= b[0]; ++i){

            cout << b[i];

        }

        cout << endl;

        */

        if(vis[b[b[]]]) return false;

        else vis[b[b[]]] = true;

        for(i = ; i <= bigg; ++i){

            if(vis[i] != ans[i])    break;

        }

        if(i == bigg + )   return true;

        cur = b[b[]];

    }

}

int main() {

    ofstream fout ("runround.out");

    ifstream fin ("runround.in");

    int i, j, k, t, n, s, c, w, q;

    fin >> num;

    ++num;

    toStr(num);

    /*

    for(i = 1; i <= a[0]; ++i){

        cout << a[i];

    }

    cout << endl;

    */

    while(!solve()){

        //cout << num << endl;

        toNum();

        ++num;

        toStr(num);

    }

    fout << num << endl;

    fin.close();

    fout.close();

    return ;

}