Codeforces Gym 100286I iSharp 模拟

原题地址：http://codeforces.com/gym/100286/attachments/download/2013/20082009-acmicpc-northeastern-european-regional-contest-neerc-08-en.pdf

题意大概就是让你把写在一块的变量分开。。水题，用string过。

详见代码：

//#include<iostream>

#include<fstream>

#include<string>

#include<algorithm>

using namespace std;

string s;

string allType;

string va,ty;

string Analyze(string v) {

    int t = ;

    while ((v[t] >= 'A' && v[t] <= 'Z') || (v[t] >= 'a' && v[t] <= 'z'))t++;

    va.assign(v.begin(), v.begin() + t);

    ty.assign(v.begin() + t, v.end());

    reverse(ty.begin(), ty.end());

    return ty + " " + va + ";";

}

string a;

int main() {

    ifstream cin("isharp.in");

    ofstream cout("isharp.out");

    cin.sync_with_stdio(false);

    getline(cin, s);

    int tmp = ;

    while (s[tmp] != ' ')tmp++;

    allType.assign(s.begin(), s.begin() + tmp);

    tmp++;

    while (true) {

        int t = tmp;

        while (s[t] != ',' && s[t] != ';')t++;

        a.assign(s.begin() + tmp, s.begin() + t);

        a = allType + Analyze(a);

        int c = ;

        for (int i = ; i < a.length(); i++) {

            if (a[i] == '[' || a[i] == ']') {

                c++;

                if (c % )cout << '[';

                else cout << ']';

            }

            else cout << a[i];

        }

        cout << endl;

        if (s[t] == ';')break;

        tmp = t + ;

    }

    return ;

}