http://acm.hdu.edu.cn/showproblem.php?pid=3446
题意:一个棋盘,有个KING,有一些能走的点,每次只能走到没走过的地方,没路可走的输,求先手是否必胜。
思路:先去掉KING的位置,只考虑其他的,如果这样求出的匹配数和加上king的匹配数一样,说明KING这个位置没有在匹配中,因此后手必胜,否则先手必胜,为什么?
可以思考一下,匹配的路径是一条:匹配,不匹配,匹配。。。不匹配,匹配,因此如果KING在匹配中,那最后一步也能够是先手走的。
#include<cstdio>
#include<cmath>
#include<cstring>
#include<iostream>
#include<algorithm>
int dx[]={-,-,-,,,,,,,-,,-,,-,,-,,-,-,};
int dy[]={-,,,,,-,-,,,,-,-,,-,-,,,-,,-};
int match[],G[][],inpath[],q[],head,tail,newbase;
int inqueue[],inblossom[],base[],father[],n;
int finish,start,R,C,kx,ky,c[];
char s[][];
int read(){
int t=,f=;char ch=getchar();
while (ch<''||ch>''){if (ch=='-') f=-;ch=getchar();}
while (''<=ch&&ch<=''){t=t*+ch-'';ch=getchar();}
return t*f;
}
int lca(int u,int v){
memset(inpath,,sizeof inpath);
while (){
u=base[u];
inpath[u]=;
if (!match[u]) break;
u=father[match[u]];
}
while (){
v=base[v];
if (inpath[v]) break;
v=father[match[v]];
}
return v;
}
void reset(int u){
while (u!=newbase){
int v=match[u];
inblossom[base[v]]=inblossom[base[u]]=;
u=father[v];
if (base[u]!=newbase) father[u]=v;
}
}
void blossomcontract(int u,int v){
newbase=lca(u,v);
memset(inblossom,,sizeof inblossom);
reset(u);
reset(v);
if (base[u]!=newbase) father[u]=v;
if (base[v]!=newbase) father[v]=u;
for (int i=;i<=n;i++)
if (inblossom[base[i]]){
base[i]=newbase;
if (!inqueue[i]) c[++tail]=i,inqueue[i]=;
}
}
void findaugmentingpath(){
memset(inqueue,,sizeof inqueue);
memset(father,,sizeof father);
for (int i=;i<=n;i++) base[i]=i;
head=;tail=;c[]=start;inqueue[start]=;
finish=;
while (head<=tail){
int u=c[head++];
for (int v=;v<=n;v++)
if (G[u][v]&&base[u]!=base[v]&&match[v]!=u){
if (v==start||(match[v]>)&&(father[match[v]]>)){
blossomcontract(u,v);
}else
if (father[v]==){
father[v]=u;
if (match[v]){
c[++tail]=match[v];inqueue[match[v]]=;
}else{
finish=v;
return;
}
}
}
}
}
void augmentpath(){
int u,v,w;
u=finish;
while (u>){
v=father[u];
w=match[v];
match[u]=v;
match[v]=u;
u=w;
}
}
int solve(){
int res=;
memset(match,,sizeof match);
for (int i=;i<=n;i++)
if (!match[i]){
start=i;
findaugmentingpath();
if (finish) augmentpath(),res++;
}
return res;
}
int main(){
int T=read(),Tcase=;
while (T--){
printf("Case #%d: daizhenyang ",++Tcase);
R=read();C=read();
memset(G,,sizeof G);
for (int i=;i<=R;i++){
scanf("%s",s[i]+);
}
for (int i=;i<=R;i++)
for (int j=;j<=C;j++)
if (s[i][j]!='#'){
for (int k=;k<;k++){
int x=i+dx[k],y=j+dy[k];
if (x>=&&x<=R&&y>=&&y<=C&&s[x][y]!='#'){
G[(i-)*C+j][(x-)*C+y]=;
G[(x-)*C+y][(i-)*C+j]=;
}
}
if (s[i][j]=='K') kx=i,ky=j;
}
n=R*C;
int t1=solve();
int x=(kx-)*C+ky;
for (int i=;i<=n;i++) if (G[x][i]) G[x][i]=G[i][x]=;
if (solve()==t1) puts("lose");
else puts("win");
}
return ;
}