Question:

Given the code :

 A = [1 2 3; 3 2 1]
B = A.^2

The output :

B =

     1     4     9
9 4 1

But if I do this : B = A^2

The output is :

Error using  ^
Inputs must be a scalar and a square matrix.
To compute elementwise POWER, use POWER (.^) instead.

What does the operator . do exactly ?

Answer:

The dot itself is not an operator, .^ is.

The .^ is a pointwise¹ (i.e. element-wise) power, as .* is the
pointwise product.

C.f.

¹) Hence the dot.

05-11 17:02