ZOJ 1122 Clock(模拟)

Clock

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Time Limit: 2 Seconds      Memory Limit: 65536 KB

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You are given a standard 12-hour clock with analog display, an hour hand and a minute hand. How many times does the minute hand pass the hour hand in a given time interval?

Sample Input

12 50  1  2

 3  8  3 20

 2 45 11  0

11  0  3 20

 1  2 12 50

 3 20  3  8

Sample Output

Program 3 by team X

Initial time  Final time  Passes

       12:50       01:02       0

       03:08       03:20       1

       02:45       11:00       8

       11:00       03:20       4

       01:02       12:50      11

       03:20       03:08      10

End of program 3 by team X

题目的下边还有一大段，当时出在HUST上，根本分不清哪输出格式是哪个，谁知道最前边最后边那句话也需要。当时有一次试了一下加上这两句，其他地方哪里又出错了。看了题解，直接把最后一次提交的错误代码， 加上这两句输出，直接A了，坑

判断分针和时针相遇的次数

代码如下：

 # include <iostream>

 # include<cstdio>

 # include<cstring>

 using namespace std;

 int main()

 {

     int a,b,c,d,ans;

     double tmp1,tmp2,tmp3,tmp4;

     printf("Program 3 by team X\n");

     printf("Initial time  Final time  Passes\n");

     while(scanf("%d%d%d%d",&a,&b,&c,&d)!= EOF)

     {

         printf("       ");

         printf("%02d:%02d",a,b);

         printf("       ");

         printf("%02d:%02d",c,d);

         printf("      ");

         if(a==)

             a=;

         if(c==)

             c=;

         tmp2 = b/60.0;

         tmp1 = a/12.0 + tmp2/12.0;

         tmp4 = d/60.0;

         tmp3 = c/12.0 + tmp4/12.0;

                if(a==c)

         {

             if(d>=b)

             {

                 if(tmp1-tmp2> && tmp4-tmp3>)

                 {

                     ans = ;

                 }

                 else

                     ans = ;

             }

             else

             {

                 ans = ;

                 if(tmp1 - tmp2 >  )

                     ans++;

                 if(tmp4-tmp3>)

                     ans ++;

             }

         }

         else if(a<c)

         {

             ans = c-a-;

             if(tmp1 - tmp2 >  )

                 ans++;

             if(tmp4 - tmp3 > )

                 ans++;

         }

         else

         {

             ans = -a + c -;

             if(tmp1 - tmp2 > )

                 ans++;

             if(tmp4 - tmp3>)

                 ans++;

         }

         printf("%2d\n",ans);

     }

     printf("End of program 3 by team X\n");

     return ;

 }