#include <stdio.h>
//(2n+1)^2 - 8m^2 = 1，佩尔函数，或者打表
int main() {
int count = ;
int x1 = , xi = , y1= , yi = , n = , txi;
while (count++ < )
{
txi = xi;
xi = x1 * xi + n * y1 * yi;
yi = x1 * yi + y1 * txi;
printf("%10d%10d\n", yi, (xi - ) / );
}
return ;
}