题目要求第n个丑数。所以对于中间结果不须要保存。def Humble(index): curHum = 1 M2 = 2; M3 = 3; M5 = 5 while index > 1: curHum = min(min(M2, M3), M5) while M2 <= curHum: M2 *= 2 while M3 <= curHum: M3 *= 3 while M5 <= curHum: M5 *= 5 index -= 1 return curHum