Android点击两次返回退出程序

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Android点击两次返回退出程序

private long mExitTime;

public boolean onKeyDown(int keyCode, KeyEvent event) {

    if (keyCode == KeyEvent.KEYCODE_BACK) {

        if ((System.currentTimeMillis() - mExitTime) > 2000) {

            Object mHelperUtils;

            Toast.makeText(this, "再按一次退出程序", Toast.LENGTH_SHORT).show();

            mExitTime = System.currentTimeMillis();

        } else {

            finish();

        }

        return true;

    }

    return super.onKeyDown(keyCode, event);

}