斐波那契数,亦称之为斐波那契数列(意大利语: Successione di Fibonacci),又称黄金分割数列、费波那西数列、费波拿契数、费氏数列,指的是这样一个数列:1、1、2、3、5、8、13、21、……在数学上,斐波那契数列以如下被以递归的方法定义:F0=0,F1=1,Fn=Fn-1+Fn-2(n>=2,n∈N*),用文字来说,就是斐波那契数列由 0 和 1 开始,之后的斐波那契数列系数就由之前的两数相加。

解题如下:

Default.aspx:

<%@ Page Language="C#" AutoEventWireup="true" CodeFile="Default.aspx.cs" Inherits="_Default" %>
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
<meta http-equiv="Content-Type" content="text/html; charset=utf-8"/>
<title></title>
</head>
<body>
<form id="form1" runat="server">
<div>
请输入n的值:<asp:TextBox runat="server" ID="sa"></asp:TextBox>
<asp:Button runat="server" ID="suit" Text="斐波那契数列" OnClick="suit_Click"/>
结果:<asp:TextBox runat="server" ID="sa1"></asp:TextBox>
</div>
</form>
</body>
</html>

Default.aspx.cs:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls; public partial class _Default : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{ }
protected void suit_Click(object sender, EventArgs e)
{
long m = Convert.ToInt64(sa.Text.Trim());
sa1.Text=""+ Fibonacci(m)+"";
}
//速度快
public static long FbnqSort2(long num)
{
long ret = ;
long num1 = ;
long num2 = ;
if (num == || num == )
{
ret = ;
}
else if (num > )
{ for (int i = ; i < num - ; i++)
{
ret = num1 + num2;
num1 = num2;
num2 = ret;
}
}
else
{
ret = ;
}
return ret;
}
//速度极慢
public static long fib(long n)
{
if (n == || n == )
{
return ;
}
else if (n > )
{
long a = fib(n - );
long b = fib(n - );
return a + b;
}
else
{
return ;
}
}
//速度快
private static long F2(long number)
{
long a = , b = ;
if (number == || number == )
{
return ;
}
else if (number > )
{
for (int i = ; i <= number; i++)
{
long c = a + b;
b = a;
a = c;
}
return a;
}
else
{
return ;
}
}
//速度快
public static long Fibonacci(long n)
{
long f0 = ;
long f1 = ;
long f2 = ;
int t = ;
if (n < )
{
return ;
}
else if (n == || n == )
{
return n;
}
else
{
while (t <= n)
{
f2 = f0 + f1;
f0 = f1;
f1 = f2;
t++;
}
return f2;
}
}
//速度极慢
public static long F1(long number)
{
if (number == || number == )
{
return ;
}
else if (number > )
{
return F1(number - ) + F1(number - );
}
else
{
return ;
}
}
}

运行结果:

斐波那契数列(C#)-LMLPHP

05-07 15:33
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