判断无向图是否存在欧拉回路,就是看度数为奇数的点有多少个,如果有两个,那么以那分别两个点为起点和终点,可以构造出一条欧拉回路,如果没有,就任意来,否则,欧拉回路不存在。
首先用并查集判断连通,然后统计度数。
#include<cstdio>
#include<cstring>
#include<vector>
//#include<algorithm>
//#define local
using namespace std; const int maxl = ;
const int maxn = 1e3 + ;
int p[maxl];
bool used[maxl];//出现过的字符 char s[maxn]; int Find(int x) {return p[x] == x ? x : p[x] = Find(p[x]); } char last(char *p)
{
while(*(++p));
return *(p-);
} int deg[maxl];//出度 - 入度
#define ID(c) (c-'a')
int main()
{
#ifdef local
freopen("in10129.txt","r",stdin);
#endif // local
int T,N;
scanf("%d",&T);
while(T--) {
memset(used,false,sizeof(used));
memset(deg,,sizeof(deg));
int cc = ;
for(int i = ; i < maxl; i ++) { p[i] = i; }
scanf("%d", &N);
while(N--){
scanf("%s",s);
int u = ID(*s), v = ID(last(s));
deg[u]++; deg[v]--;
used[u] = used[v] = true;
int s1 = Find(u), s2 = Find(v);
if(s1 != s2) {
p[s1] = s2; cc--;
}
}
bool ok = false;
for(int i = ; i < maxl; i ++) {
if(!used[i]) cc--;
}
int odd[maxl] = {},top = ;
if(cc == ){
for(int i = ; i < maxl; i ++) if(deg[i]) {
odd[top++] = deg[i];
}
if(top == && (odd[] == || odd[] == ) ) ok = true;//入度sum = 出度sum
else if(top == ) ok = true;
}
if(ok) printf("Ordering is possible.\n");
else printf("The door cannot be opened.\n");
}
return ;
}