好久没有1A题啦♪(^∇^*)
一个sb建图,我居然调样例调了10min
看起来是双向边,其实在建图的时候要当成有向图,
否则他会时间倒流(233)
把每个点裂成k个点,然后把每条边裂成4条边(正向反向&膜不膜)
(话说我好像不会用openlivewriter贴代码,尴尬了)
#include <bits/stdc++.h>
#define poi(x,y) ((x)*(k+1)+(y))
#define st poi(1,0)
#define INF 2000000000
using namespace std;
int n,m,k,E;
int from[],to[],nex[];
int fir[],d[],w[];
void add(int x,int y,int z)
{
from[++E]=x;to[E]=y;w[E]=z;nex[E]=fir[x];fir[x]=E;
}
int work()
{
for(int i=;i<=poi(n,k);i++)
d[i]=INF;
d[st]=;
priority_queue<pair<int,int> > q;
for(int i=fir[st];i;i=nex[i])
q.push(make_pair(-w[i],i));
while(!q.empty())
{
int tem=q.top().second;q.pop();
if(to[tem]>=poi(n,))
int e=;
if(d[from[tem]]!=INF && d[from[tem]]+w[tem]<d[to[tem]])
{
d[to[tem]]=d[from[tem]]+w[tem];
for(int i=fir[to[tem]];i;i=nex[i])
q.push(make_pair(-w[i],i));
}
}
return d[poi(n,k)];
}
int main()
{
scanf("%d%d%d",&n,&m,&k);
for(int i=;i<=m;i++)
{
int from,to,wei;
scanf("%d%d%d",&from,&to,&wei);
for(int j=;j<k;j++)
add(poi(from,j),poi(to,j+),wei/),
add(poi(to,j),poi(from,j+),wei/);
for(int j=;j<=k;j++)
add(poi(from,j),poi(to,j),wei),
add(poi(to,j),poi(from,j),wei);
}
for(int i=;i<k;i++)
add(poi(n,i),poi(n,k),);
printf("%d\n",work());
return ;
}