【LeetCode】039. Combination Sum

题目：

Given a set of candidate numbers (C) (without duplicates) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.

The same repeated number may be chosen from C unlimited number of times.

Note:

• All numbers (including target) will be positive integers.
• The solution set must not contain duplicate combinations.

For example, given candidate set [2, 3, 6, 7] and target 7, 
A solution set is:

[

  [7],

  [2, 2, 3]

]

　　

题解：

Solution 1 ()

class Solution {

public:

    void dfs(vector<vector<int>>& vv, vector<int>& v, vector<int> candidates, int target, int sum) {

        if(sum == target) {

            vector<int>* tmp = new vector<int>;

            *tmp = v;

            sort((*tmp).begin(), (*tmp).end());

            if(find(vv.begin(), vv.end(), *tmp) == vv.end())

                vv.push_back(*tmp);

            delete tmp;

            return;

        }

        if(sum > target) return;

        for(int i=; i<candidates.size(); ++i) {

            v.push_back(candidates[i]);

            dfs(vv, v, candidates, target, sum+candidates[i]);

            v.pop_back();

        }

    }

    vector<vector<int>> combinationSum(vector<int>& candidates, int target) {

        vector<vector<int>> vv;

        vector<int> v;

        dfs(vv, v, candidates, target, );

        return vv;

    }

};