【Unity】优化 if else 和 Switch Case

1. 使用字典进行优化

   • 方法优化：

   //注册字典，通过Action作为值，然后进行回调
   private Dictionary<int, Action<CharacterEntity>> animationActions =
               new Dictionary<int, Action<CharacterEntity>>()
               {
                   { 0, (character) => character.animator.SetTurnUp() },
                   { 1, (character) => character.animator.SetTurnDown() },
                   { 2, (character) => character.animator.SetTurnRight() },
                   { 3, (character) => character.animator.SetTurnLeft() }
               };
   
   /****************调用方法****************/
   //通过对字典判空
   //传参执行回调
   private void UpdatePlayerAnimation(CharacterEntity character, int id)
           {
               if (animationActions.TryGetValue(id, out var action))
               {
                   action(character);
               }
           }
   

2. 使用数组进行优化：

   • 优化坐标：

   //创建坐标数组
   private Vector3[] _positionOffsets = new Vector3[]
           {
               new Vector3(0, 1f, 0),
               new Vector3(0, -0.2f, 0),
               new Vector3(-0.7f, 0, 0),
               new Vector3(0.7f, 0, 0)
           };
   
   //直接通过id调用即可
   transform.position = pos + _positionOffsets[id];