力扣题:字符串的反转-11.22

力扣题-11.22

[力扣刷题攻略] Re：从零开始的力扣刷题生活

力扣题1：541. 反转字符串 II

解题思想：进行遍历翻转即可

class Solution(object):
    def reverseStr(self, s, k):
        """
        :type s: str
        :type k: int
        :rtype: str
        """
        t = list(s)
        for i in range(0, len(t), 2 * k):
            t[i: i + k] = reversed(t[i: i + k])
        return "".join(t)

class Solution {
public:
    string reverseStr(string s, int k) {
        int n = s.length();
        for (int i = 0; i < n; i += 2 * k) {
            reverse(s.begin() + i, s.begin() + min(i + k, n));
        }
        return s;
    }
};