做作业的时候,邻座的小盆友问你:“五乘以七等于多少?”你应该不失礼貌地围笑着告诉他:“五十三。”本题就要求你,对任何一对给定的正整数,倒着输出它们的乘积。
输入格式:
输入在第一行给出两个不超过 1000 的正整数 A 和 B,其间以空格分隔。
输出格式:
在一行中倒着输出 A 和 B 的乘积。
输入样例:
5 7
输出样例:
53
C:
#include<stdio.h>
int main()
{
int a,b,n;
int A,count=0;
scanf("%d %d",&a,&b);
n=a*b;
while(n!=0)
{
A=n%10;
n=n/10;
if(A==0&&count==0)
{
continue;
}
count++;
printf("%d",A);
}
return 0;
}
C++:
#include <iostream>
using namespace std;
int main() {
int a, b, n;
int A, count = 0;
cin >> a >> b;
n = a * b;
while (n != 0) {
A = n % 10;
n = n / 10;
if (A == 0 && count == 0) {
continue;
}
count++;
cout << A;
}
return 0;
}
Java:
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int a = scanner.nextInt();
int b = scanner.nextInt();
int n = a * b;
int A, count = 0;
while (n != 0) {
A = n % 10;
n = n / 10;
if (A == 0 && count == 0) {
continue;
}
count++;
System.out.print(A);
}
}
}
Python:
a, b = map(int, input().split())
n = a * b
count = 0
while n != 0:
A = n % 10
n = n // 10
if A == 0 and count == 0:
continue
count += 1
print(A, end='')