我们知道C++可以对函数进行重载,让同名的函数来完成相同的基本操作。其实运算符也是可以重载的,而且有的运算符已经在使用了,就像*,既可以用于地址,又可以用于乘法。
运算符重载需要使用关键字operator
语法如下
Type operator Sign(const Type p1, const Type p2)
{
Type ret;
return ret;
}
Sign指的是+ - * / 等操作符
复数类开发
如果我们需要计算两个复数的运算,就需要进行操作符重载了,因为常规的+ -不能直接进行复数运算。
#ifndef COMPLEX_H
#define COMPLEX_H
class Complex
{
private:
int a;
int b;
public:
Complex();
Complex(int a, int b);
int getA();
int getB();
friend Complex operator+ (const Complex& p1, const Complex& p2);
};
Complex operator+ (const Complex& p1, const Complex& p2);
#endif // COMPLEX_H
#include "complex.h"
Complex::Complex(int a, int b)
{
this->a = a;
this->b = b;
}
Complex::Complex()
{
a = 0;
b = 0;
}
int Complex::getA()
{
return a;
}
int Complex::getB()
{
return b;
}
//+操作符重载,两个复数相加,实部与实部相加,虚部与虚部相加
//operator+相当于函数名,
//但是使用的时候直接使用+就可以
Complex operator+(const Complex& p1, const Complex& p2)
{
Complex ret;
ret.a = p1.a + p2.a;
ret.b = p1.b + p2.b;
return ret;
}
#include <iostream>
#include "complex.h"
using namespace std;
int main()
{
Complex c1(1, 2);
Complex c2(3, 4);
//Complex c3 = operator+(c1,c2);
Complex c3 = c1+c2; //与上面的语句等效
cout <<" c3.getA():"<< c3.getA() << endl;
cout <<" c3.getB():"<< c3.getB() << endl;
return 0;
}
分析:语句Complex c3 = operator+(c1,c2); 和语句Complex c3 = c1+c2;效果是一样的,本来复数是不能直接加减的,但是进行了+ 操作符重载,在进行复数运算是编译器法相不能直接+,就去看你有没有炒作符重载,有的话就直接拿来用。
上面的代码用的友元,在C++中友元是要慎用的,,可以将操作符重载函数直接定义为类的成员函数也是可以运行的,如下所示:
#ifndef COMPLEX_H
#define COMPLEX_H
class Complex
{
private:
int a;
int b;
public:
Complex();
Complex(int a, int b);
int getA();
int getB();
Complex operator+(const Complex& p);
};
#endif // COMPLEX_H
#include "complex.h"
Complex::Complex(int a, int b)
{
this->a = a;
this->b = b;
}
Complex::Complex()
{
a = 0;
b = 0;
}
int Complex::getA()
{
return a;
}
int Complex::getB()
{
return b;
}
//+操作符重载,两个复数相加,实部与实部相加,虚部与虚部相加
//operator+相当于函数名,
//但是使用的时候直接使用+就可以
Complex Complex::operator+(const Complex& p)
{
Complex ret;
ret.a = this->a + p.a;
//等效于ret.a = a + p.a;
ret.b = this->b + p.b;
//等效于ret.b = b + p.b;
return ret;
}
友元函数与操作符重载函数对比
友元函数:friend Complex operator+ (const Complex& p1, const Complex& p2);
使用友源函数,需要左操作数p1和右操作数p2
类操作符重载函数:Complex operator+(const Complex& p);
使用类内部操作符重载函数,参数只有一个p,作为右操作数,左操作数就是本身this。
时间类开发
下面一个时间类,也进行时间的相关运算,时与时相加减,分钟与分钟相加减
#ifndef MYTIME_H
#define MYTIME_H
#include <iostream>
using namespace std;
class Time
{
private:
int hours;
int minutes;
public:
Time();
Time(int h, int m = 0);
void AddMin(int m);
void AddHr(int h);
void Reset(int h = 0, int m = 0);
Time Sum(const Time& t) const;
void Show() const;
};
#endif // MYTIME_H
#include "mytime.h"
Time::Time()
{
hours = minutes = 0;
}
Time::Time(int h, int m)
{
hours = h;
minutes = m;
}
void Time::AddMin(int m)
{
minutes += m;
hours += minutes/60;
minutes %= 60;
}
void Time::AddHr(int h)
{
hours += h;
}
void Time::Reset(int h, int m)
{
hours = h;
minutes = m;
}
Time Time::Sum(const Time &t) const
{
Time sum;
sum.minutes = minutes + t.minutes;
sum.hours = hours + t.hours + sum.minutes/60;
sum.minutes %= 60;
return sum;
}
void Time::Show() const
{
cout << hours << " hours, " << minutes << " minutes.\n";
}
#include <iostream>
#include "mytime.h"
using namespace std;
int main()
{
Time planning;
Time coding(2, 40);
Time fixing(5, 55);
Time total;
cout << "planning time = ";
planning.Show();
cout << endl;
cout << "coding time = ";
coding.Show();
cout << endl;
cout << "fixing time = ";
fixing.Show();
cout << endl;
total = coding.Sum(fixing);
cout << "coding.Sum(fixing) = ";
total.Show();
cout << endl;
return 0;
}
输出结果
planning time = 0 hours, 0 minutes.
coding time = 2 hours, 40 minutes.
fixing time = 5 hours, 55 minutes.
coding.Sum(fixing) = 8 hours, 35 minutes.
添加加法运算符
将Time类转换为重载的加法运算法很容易,只要将Sum()的名称改为operator +()即可。只要把运算符+放在operator的后面
#ifndef STOCK_H
#define STOCK_H
#include <string>
using namespace std;
class stock
{
private:
string company;
long shares;
double share_val;
double total_val;
void set_tot() {total_val = shares * share_val;}
public:
void buy(long num, double price);
void sell(long num, double price);
void update(double price);
void show() const;
Time operator+(const Time& t) const;
const stock& topval(const stock& s) const;
stock(const string& co, long n, double pr);
stock();
~stock();
};
#endif // STOCK_H
#include "mytime.h"
Time::Time()
{
hours = minutes = 0;
}
Time::Time(int h, int m)
{
hours = h;
minutes = m;
}
void Time::AddMin(int m)
{
minutes += m;
hours += minutes/60;
minutes %= 60;
}
void Time::AddHr(int h)
{
hours += h;
}
void Time::Reset(int h, int m)
{
hours = h;
minutes = m;
}
//运算符+重载
Time Time::operator+(const Time &t) const
{
Time sum;
sum.minutes = minutes + t.minutes;
sum.hours = hours + t.hours + sum.minutes/60;
sum.minutes %= 60;
return sum;
}
void Time::Show() const
{
cout << hours << " hours, " << minutes << " minutes.\n";
}
operator+(const Time &t) const与Sum(const Time &t) const效果完全一样,可以理解operator+()就是一个函数,也可以被调用。就像下面的语句一样。
total = coding.operator+(fixing);
但是可以进一步简化
total = coding + fixing;
这两种方法都讲使用operator+()函数,运算符左侧的coding是调用对象,右边的fixing是参数被传递的对象。
#include <iostream>
#include "mytime.h"
using namespace std;
int main()
{
Time planning;
Time coding(2, 40);
Time fixing(5, 55);
Time total;
cout << "planning time = ";
planning.Show();
cout << endl;
cout << "coding time = ";
coding.Show();
cout << endl;
cout << "fixing time = ";
fixing.Show();
cout << endl;
//total = coding.operator+(fixing);
total = coding + fixing;
cout << "coding.Sum(fixing) = ";
total.Show();
cout << endl;
return 0;
}
输出结果没有变化
planning time = 0 hours, 0 minutes.
coding time = 2 hours, 40 minutes.
fixing time = 5 hours, 55 minutes.
coding.Sum(fixing) = 8 hours, 35 minutes.
运算符重载的限制:
1、重载后的运算符必须至少有一个操作数是用户定义的类型;
2、使用运算符使不能违反运算符原来的句法规则;
3、不能创建新的运算符;
4、有些运算符不能被重载:如sizeof, ?:, ::等
5、大多数运算符都可以通过成员或者非成员函数进行重载,但=、()、[]、->只能通过成员函数进行重载。
+ 、-、 *重载的应用
#ifndef MYTIME_H
#define MYTIME_H
#include <iostream>
using namespace std;
class Time
{
private:
int hours;
int minutes;
public:
Time();
Time(int h, int m = 0);
void AddMin(int m);
void AddHr(int h);
void Reset(int h = 0, int m = 0);
Time operator+(const Time& t) const;
Time operator-(const Time& t) const;
Time operator*(double mult) const;
void Show() const;
};
#endif // MYTIME_H
#include "mytime.h"
Time::Time()
{
hours = minutes = 0;
}
Time::Time(int h, int m)
{
hours = h;
minutes = m;
}
void Time::AddMin(int m)
{
minutes += m;
hours += minutes/60;
minutes %= 60;
}
void Time::AddHr(int h)
{
hours += h;
}
void Time::Reset(int h, int m)
{
hours = h;
minutes = m;
}
//运算符+重载
Time Time::operator+(const Time &t) const
{
Time sum;
sum.minutes = minutes + t.minutes;
sum.hours = hours + t.hours + sum.minutes/60;
sum.minutes %= 60;
return sum;
}
Time Time::operator-(const Time& t) const
{
Time diff;
int tot1, tot2;
tot1 = t.minutes + 60 * t.hours;
tot2 = minutes + 60 * hours;
diff.minutes = (tot2 - tot1) % 60;
diff.hours = (tot2 - tot1) / 60;
return diff;
}
Time Time::operator*(double mult) const
{
Time result;
long totalminutes = hours * mult *60 + minutes * mult;
result.hours = totalminutes / 60;
result.minutes = totalminutes % 60;
return result;
}
void Time::Show() const
{
cout << hours << " hours, " << minutes << " minutes.\n";
}
#include <iostream>
#include "mytime.h"
using namespace std;
int main()
{
Time weeding(4, 35);
Time waxing(2, 47);
Time total;
Time diff;
Time adjusted;
cout << "weeding time = ";
weeding.Show();
cout << endl;
cout << "waxing time = ";
waxing.Show();
cout << endl;
cout << "total working time = ";
total = weeding + waxing;
total.Show();
cout << endl;
diff = weeding - waxing;
cout << "weeding time - waxing time = ";
diff.Show();
cout << endl;
adjusted = total * 1.5;
cout << "adjusted work time = ";
adjusted.Show();
cout << endl;
return 0;
}
输出结果
weeding time = 4 hours, 35 minutes.
waxing time = 2 hours, 47 minutes.
total working time = 7 hours, 22 minutes.
weeding time - waxing time = 1 hours, 48 minutes.
adjusted work time = 11 hours, 3 minutes.