网易编程题——Fibonacci数列

#include <iostream>

using namespace std;

int main() {

    int N;

    cin >> N;

    int one = 0;

    int two = 1;

    while (1) {

        if (N >= one && N <= two) {

            cout << min(two - N, N - one) << endl;

            break;

        }

        int sum = one + two;

        one = two;

        two = sum;

    }

    return 0;

}