Java Lambda map返回部分属性

通过map，返回部分属性。

MyUser，作为源数据

MyUserS，作为返回的新数据。

@Test

    public void Test1()

    {

        List<MyUser> ulist=new ArrayList<>();

        MyUser u1=new MyUser();

        u1.setName("1");u1.setAge(1);u1.setHobby("swimming");

        MyUser u2=new MyUser();

        u2.setName("2");u2.setAge(2);u2.setHobby("sleeping");

        MyUser u3=new MyUser();

        u3.setName("3");u3.setAge(3);u3.setHobby("playing");

        ulist.add(u1);ulist.add(u2);ulist.add(u3);

        List<MyUserS> usList=ulist.stream().map(x->{return new MyUserS(x.getName(),x.getAge());}).collect(Collectors.toList());

    }

    @Data

    public class MyUser

    {

        public String name;

        public Integer age;

        public String hobby;

    }

    @Data

    public class MyUserS

    {

        public MyUserS(String name,Integer age)

        {

            this.name=name;

            this.age=age;

        }

        public String name;

        public Integer age;

    }