Problem Description
Little Q's clock is alarming! It's time to get up now! However, after reading the time on the clock, Little Q lies down and starts sleeping again. Well, he has 5 alarms, and it's just the first one, he can continue sleeping for a while.
Little Q's clock uses a standard 7-segment LCD display for all digits, plus two small segments for the '':'', and shows all times in a 24-hour format. The '':'' segments are on at all times.
Your job is to help Little Q read the time shown on his clock.
Input
The first line of the input contains an integer T(1≤T≤1440), denoting the number of test cases.
In each test case, there is an 7×21 ASCII image of the clock screen.
All digit segments are represented by two characters, and each colon segment is represented by one character. The character ''X'' indicates a segment that is on while ''.'' indicates anything else. See the sample input for details.
Output
For each test case, print a single line containing a string t in the format of HH:MM, where t(00:00≤t≤23:59), denoting the time shown on the clock.
Sample Input
1
.XX...XX.....XX...XX.
X..X....X......X.X..X
X..X....X.X....X.X..X
......XX.....XX...XX.
X..X.X....X....X.X..X
X..X.X.........X.X..X
.XX...XX.....XX...XX.
Sample Output
02:38
题意：把字符串翻译成时间。
题解：直接利用他们的区别判断即可。
#include <iostream>
#include<cstdio>
#include<algorithm>
#include<queue>
#include<map>
#include<vector>
#include<cmath>
#include<cstring>
using namespace std; char time[+][+];
int check(int i)
{
int j;
if(time[][i]=='X')
{
if(time[][i+]=='.')
return ;
else if(time[][i]=='.')
return ;
else if(time[][i+]=='.')
return ;
else
return ;
}
else
{
if(time[][i]=='X')
{
if(time[][i+]=='X')
{
if(time[][i+]=='X')
return ;
else
return ;
}
else
return ;
}
else
{
if(time[][i+]=='.')
{
if(time[][i+]=='X')
return ;
else
return ;
}
else
return ;
}
}
} int main()
{
int a,b,c,d;
int T;
scanf("%d",&T);
while(T--)
{
for(int i=;i<=;i++)
for(int j=;j<=;j++)
cin>>time[i][j];
a=check();
b=check();
c=check();
d=check();
printf("%d%d:%d%d\n",a,b,c,d);
}
return ;
}