【C语言】项目实战——快速0基础上手五子棋游戏(内附源码)

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五子棋的实战

• 前言
• 一.上回三子棋的源码
• 二.五子棋
• • 1.棋盘大小
  • 2.判断胜负条件
  • 3.试玩一下
  • 4.五子棋的源码
• 总结

前言

一.上回三子棋的源码

• 上回讲过的东西就不再缀叙了，详情请看上方链接，这里就只把上回的源码贴出来方便大家更好的理解之后的内容。
• 以下为三子棋具体的每个文件中的源码哦,需要自取

1.game.h(头文件)

#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#define Col 3
#define Row 3
void InitBoard(char board[Row][Col], int row, int col);//初始化棋盘
void PrintBoard(char board[Row][Col], int row, int col);//打印棋盘
void PlayBoard(char board[Row][Col], int row, int col);//玩游戏
void ComputerBoard(char board[Row][Col], int row, int col);//电脑下
int IsFull(char board[Row][Col], int row, int col);//棋盘是否已满
int Is_Win(char board[Row][Col], int row, int col);//判断谁赢

---

2.game.c（定义函数的文件）

#include"game.h"
void InitBoard(char board[Row][Col], int row, int col)
{
	int i = 0;
	int j = 0;
	for (i = 0; i < row; i++)
	{
		for (j =0; j < col; j++)
		{
			board[i][j] = ' ';

		}
	}
}


void PrintBoard(char board[Row][Col], int row, int col)
{
	int i = 0;
	
	//打印数据
	for (i = 0; i < row; i++)
	{
		int j = 0;
		for (j = 0; j < col; j++)
		{
			printf(" %c ", board[i][j]);
			if (j < col - 1)
				printf("|");

		}
		printf("\n");

		if (i < row - 1)
		{
			int j = 0;
			for (j = 0; j < col; j++)
			{
				printf("---");
				if (j < col - 1)
					printf("|");
			}
			printf("\n");
		}
	}
}

void PlayBoard(char board[Row][Col], int row, int col)
{
	int x, y = 0;
	while (1)
	{
		printf("玩家下棋>:\n");
		printf("请输入要下的坐标，中间用空格隔开\n");
		scanf("%d %d", &x, &y);
		//判断输入坐标的合法性
		if (x >= 1 && x <= row && y >= 1 && y <= col)
		{
			if (board[x - 1][y - 1] == ' ')
			{
				board[x - 1][y - 1] = '*';
				break;
			}
			else
				printf("坐标已被占用，请重新输入\n");
		}
		else
			printf("坐标非法，请重新输入\n");

	}

}


void ComputerBoard(char board[Row][Col], int row, int col)
{
	int x = 0;
	int y = 0;
	printf("电脑下棋:>\n");
	while(1)
	{
		x = rand() % row;//生成0-row-1的数
		y = rand() % col;//生成0-col-1的数
		
		if (board[x][y] == ' ')
		{
			board[x][y] = '#';
			break;
		}

	}



}
int IsFull(char board[Row][Col], int row, int col)
{
	int i ,j;
	for (i = 0; i < row; i++)
	{
		for (j = 0; j < col; j++)
		{
			if (board[i][j] == ' ')
				return 0;
		}
	}
	return 1;
}


int Is_Win(char board[Row][Col], int row, int col)
{
	int x = 0;
	int y = 0;
	//竖着
	if (board[x][0] == board[x][1] && board[x][1] == board[x][2] && board[x][0] !=' ')
	{
		return board[x][0];
	}
	//横着
	if (board[0][y] == board[1][y] && board[1][y] == board[2][y] && board[0][y] != ' ')
	{
		return board[0][y];
	}
	//对角线
	if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1] != ' ')
		return board[1][1];
	if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[1][1] != ' ')
		return board[1][1];

	if (IsFull(board, row, col) == 1)
	{
		return 'Q';
	}
	return 'C';

}

---

3.test.c（主文件）

#include"game.h"
void menu()//打印菜单
{
	printf("*****************************\n");
	printf("*********** 1.play **********\n");
	printf("*********** 0.exit **********\n");
	printf("*****************************\n");

}

void game()
{
	char board[Row][Col] = { 0 };
	InitBoard(board, Row, Col);
	PrintBoard(board,Row, Col);
	char ret = 0;
	while (1)
	{
		PlayBoard(board, Row, Col);
		PrintBoard(board, Row, Col);
		ret = Is_Win(board, Row, Col);
		if (ret != 'C')
		break; 
		
		ComputerBoard(board, Row, Col);
		PrintBoard(board, Row, Col);
		ret = Is_Win(board, Row, Col);
		if (ret != 'C')
		break;
	}
	if (ret == '*')
		printf("玩家赢\n");
	if (ret == '#')
		printf("电脑赢\n");
	if (ret == 'Q')
		printf("平局\n");
}
int main()
{
	srand((unsigned int)time(NULL));
	int input = 0;
	
	do {
		
		menu();
		printf("请选择:> ");
		scanf("%d",&input);
		switch (input)
		{
		case 1:
			game();		
			break;
		case 0:
			printf("退出游戏\n");
			break;
			
		default:
			printf("输入错误，请重新输入\n");
			break;
		}
	}while(input);


	return 0;
}

• 看看游戏效果

二.五子棋

1.棋盘大小

• 三子棋的棋盘大小是3*3的，对于五子棋来说显然不够，这下咱们之前定义的Row与Col就发挥了作用，当我们想改变棋盘大小时，只需要改变它俩的值即可！

#define Col 10
#define Row 10

• 效果如图，如果你还想改的更大一点，当然也可以
• 15*15的棋盘
  
• 这一步完成

2.判断胜负条件

• 我们现在既然是五子棋，那么判断胜负的条件自然也要变化一下啦，我们先回顾一下三子棋中判断胜负的函数

int IsFull(char board[Row][Col], int row, int col)
{
	int i ,j;
	for (i = 0; i < row; i++)
	{
		for (j = 0; j < col; j++)
		{
			if (board[i][j] == ' ')
				return 0;
		}
	}
	return 1;
}


int Is_Win(char board[Row][Col], int row, int col)
{
	int x = 0;
	int y = 0;
	//竖着
	if (board[x][0] == board[x][1] && board[x][1] == board[x][2] && board[x][0] !=' ')
	{
		return board[x][0];
	}
	//横着
	if (board[0][y] == board[1][y] && board[1][y] == board[2][y] && board[0][y] != ' ')
	{
		return board[0][y];
	}
	//对角线
	if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1] != ' ')
		return board[1][1];
	if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[1][1] != ' ')
		return board[1][1];

	if (IsFull(board, row, col) == 1)
	{
		return 'Q';
	}
	return 'C';

}

• 首先我们的判定要从三子改为五子
• 其次，我们发现，上面的代码不具有灵活性，注意这里：

//竖着
	if (board[x][0] == board[x][1] && board[x][1] == board[x][2] && board[x][0] !=' ')
	{
		return board[x][0];
	}
	//横着
	if (board[0][y] == board[1][y] && board[1][y] == board[2][y] && board[0][y] != ' ')
	{
		return board[0][y];
	}
	//对角线
	if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1] != ' ')
		return board[1][1];
	if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[1][1] != ' ')
		return board[1][1];

• 
  
• 此时我们已经获胜了，但是程序却没有判定我们胜利
• 改进代码如下：

int Is_Win(char board[Row][Col], int row, int col)
{
	int i = 0;
	int j = 0;
	//竖着
	if (j < col - 4)//防止越界
	if (board[i][j] == board[i][j + 1] && board[i][j] ==board[i][j + 2]&& board[i][j] == board[i][j + 3] && board[i][j]== board[i][j + 4])
			return board[i][j];

	
	//横着
	if (i < row - 4)
	    if(board[i][j] == board[i][j + 1] && board[i][j] ==board[i][j + 2]&& board[i][j] == board[i][j + 3] && board[i][j]== board[i][j + 4])
	     return board[i][j];
	//左对角线连成五子
	if (i < row - 4 && j < col - 4)
		if (board[i][j] ==board[i + 1][j + 1] && board[i][j] ==board[i + 2][j + 2]&& board[i][j] == board[i + 3][j + 3] && board[i][j] == board[i + 4][j + 4])
			return board[i][j];
	// 右对角线连成五子 
	if (i < row - 4 && j > 4)
		if (board[i][j] == board[i + 1][j - 1] &&board[i][j] ==board[i + 2][j - 2]&& board[i][j] == board[i + 3][j - 3] && board[i][j] == board[i + 4][j - 4])
			return board[i][j];
	
	if (IsFull(board, row, col) == 1)
	{
		return 'Q';
	}
	return 'C';

}

• 把三子变成了五子，同时增加了代码的灵活性，方便我们以后玩六子棋等什么的。

3.试玩一下

• 游戏效果如图
  
• 虽然格子简陋一点，但是我们需要的功能完美实现！

4.五子棋的源码

• 下面把源码给大家分享一下，方便大家试玩以及修改自己在编写时可能出现的错误

game.h(五子棋头文件)

#define _CRT_SECURE_NO_WARNINGS 1
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#define Col 10
#define Row 10
void InitBoard(char board[Row][Col], int row, int col);//初始化棋盘
void PrintBoard(char board[Row][Col], int row, int col);//打印棋盘
void PlayBoard(char board[Row][Col], int row, int col);//玩游戏
void ComputerBoard(char board[Row][Col], int row, int col);//电脑下
int IsFull(char board[Row][Col], int row, int col);//棋盘是否已满
int Is_Win(char board[Row][Col], int row, int col);//判断谁赢

---

test.c(测试五子棋的主函数文件)

#include"game.h"
void menu()//打印菜单
{
	printf("*****************************\n");
	printf("*********** 1.play **********\n");
	printf("*********** 0.exit **********\n");
	printf("*****************************\n");

}

void game()
{
	char board[Row][Col] = { 0 };
	InitBoard(board, Row, Col);
	PrintBoard(board, Row, Col);
	char ret = 0;
	while (1)
	{
		PlayBoard(board, Row, Col);
		PrintBoard(board, Row, Col);
		ret = Is_Win(board, Row, Col);
		if (ret != 'C')
			break;

		ComputerBoard(board, Row, Col);
		PrintBoard(board, Row, Col);
		ret = Is_Win(board, Row, Col);
		if (ret != 'C')
			break;
	}
	if (ret == '*')
		printf("玩家赢\n");
	if (ret == '#')
		printf("电脑赢\n");
	if (ret == 'Q')
		printf("平局\n");
}
int main()
{
	srand((unsigned int)time(NULL));
	int input = 0;

	do {

		menu();
		printf("请选择:> ");
		scanf("%d", &input);
		switch (input)
		{
		case 1:
			game();
			break;
		case 0:
			printf("退出游戏\n");
			break;

		default:
			printf("输入错误，请重新输入\n");
			break;
		}
	} while (input);


	return 0;
}

---

game.c（五子棋函数的定义文件）

#include"game.h"
void InitBoard(char board[Row][Col], int row, int col)
{
	int i = 0;
	int j = 0;
	for (i = 0; i < row; i++)
	{
		for (j = 0; j < col; j++)
		{
			board[i][j] = ' ';

		}
	}
}


void PrintBoard(char board[Row][Col], int row, int col)
{
	int i = 0;

	//打印数据
	for (i = 0; i < row; i++)
	{
		int j = 0;
		for (j = 0; j < col; j++)
		{
			printf(" %c ", board[i][j]);
			if (j < col - 1)
				printf("|");

		}
		printf("\n");

		if (i < row - 1)
		{
			int j = 0;
			for (j = 0; j < col; j++)
			{
				printf("---");
				if (j < col - 1)
					printf("|");
			}
			printf("\n");
		}
	}
}

void PlayBoard(char board[Row][Col], int row, int col)
{
	int x, y = 0;
	while (1)
	{
		printf("玩家下棋>:\n");
		printf("请输入要下的坐标，中间用空格隔开\n");
		scanf("%d %d", &x, &y);
		//判断输入坐标的合法性
		if (x >= 1 && x <= row && y >= 1 && y <= col)
		{
			if (board[x - 1][y - 1] == ' ')
			{
				board[x - 1][y - 1] = '*';
				break;
			}
			else
				printf("坐标已被占用，请重新输入\n");
		}
		else
			printf("坐标非法，请重新输入\n");

	}

}


void ComputerBoard(char board[Row][Col], int row, int col)
{
	int x = 0;
	int y = 0;
	printf("电脑下棋:>\n");
	while (1)
	{
		x = rand() % row;//生成0-row-1的数
		y = rand() % col;//生成0-col-1的数

		if (board[x][y] == ' ')
		{
			board[x][y] = '#';
			break;
		}

	}



}
int IsFull(char board[Row][Col], int row, int col)
{
	int i, j;
	for (i = 0; i < row; i++)
	{
		for (j = 0; j < col; j++)
		{
			if (board[i][j] == ' ')
				return 0;
		}
	}
	return 1;
}


int Is_Win(char board[Row][Col], int row, int col)
{
	int i = 0;
	int j = 0;
	//竖着
	if (j < col - 4)//防止越界
	if (board[i][j] == board[i][j + 1] && board[i][j] ==board[i][j + 2]&& board[i][j] == board[i][j + 3] && board[i][j]== board[i][j + 4])
			return board[i][j];

	
	//横着
	if (i < row - 4)
	    if(board[i][j] == board[i][j + 1] && board[i][j] ==board[i][j + 2]&& board[i][j] == board[i][j + 3] && board[i][j]== board[i][j + 4])
	     return board[i][j];
	//左对角线连成五子
	if (i < row - 4 && j < col - 4)
		if (board[i][j] ==board[i + 1][j + 1] && board[i][j] ==board[i + 2][j + 2]&& board[i][j] == board[i + 3][j + 3] && board[i][j] == board[i + 4][j + 4])
			return board[i][j];
	// 右对角线连成五子 
	if (i < row - 4 && j > 4)
		if (board[i][j] == board[i + 1][j - 1] &&board[i][j] ==board[i + 2][j - 2]&& board[i][j] == board[i + 3][j - 3] && board[i][j] == board[i + 4][j - 4])
			return board[i][j];
	
	if (IsFull(board, row, col) == 1)
	{
		return 'Q';
	}
	return 'C';

}

---

总结

• 结合咱们上回三子棋实现的详解，其实五子棋也没啥难的，如果你上次的三子棋没有自己独立的编写过，真的墙裂建议你试试五子棋的，毕竟代码只有自己亲手编写过了才能真正做到对它的理解。
• 以上就是今天的所有内容了，如果你有任何疑问欢迎在评论区指出或者私信我，我看到后会第一时间回复的哦！

（可莉请求你们三连支持一下博主！！！点击下方评论点赞收藏帮帮可莉吧）