一种网络流建图的思路吧,改天最好整理一波网络流建图思路

 #include <bits/stdc++.h>
using namespace std;
int n,h,t,a1,a2,an,b1,b2,bn,flow,now;char ch;
int dis[],l[],d[][];char c[][];
char getch()
{
for(ch=getchar();ch!='O' && ch!='N' && ch!='X';ch=getchar());
return ch;
}
bool bfs()
{
for(int i=;i<=n+;i++)
dis[i]=;
for(h=,t=,l[]=,dis[]=;h<=t;h++)
for(int i=;i<=n+;i++)
if(d[l[h]][i] && !dis[i])
l[++t]=i,dis[i]=dis[l[h]]+;
return dis[n+];
}
int dfs(int now,int maxflow)
{
if(now==n+) return maxflow;
int flow=;
for(int i=;i<=n+;i++)
if(dis[i]==dis[now]+ && d[now][i])
{
int thi=dfs(i,min(maxflow,d[now][i]));
d[now][i]-=thi;d[i][now]+=thi;
maxflow-=thi;flow+=thi;
if(maxflow==) return flow;
}
if(flow==)
dis[now]=-;
return flow;
}
void INIT()
{
for(int i=;i<=n;i++)
for(int j=;j<=n;j++)
switch(c[i][j])
{
case'O':d[j][i]=d[i][j]=;break;
case'N':d[j][i]=d[i][j]=flow;break;
case'X':d[j][i]=d[i][j]=;break;
}
for(int i=;i<=n+;i++)
d[][i]=d[i][]=d[i][n+]=d[n+][i]=;
d[a1][]=d[][a1]=an<<;d[b1][]=d[][b1]=bn<<;
d[a2][n+]=d[n+][a2]=an<<;d[b2][n+]=d[n+][b2]=bn<<;
now=;
}
int main()
{
while(~scanf("%d%d%d%d%d%d%d",&n,&a1,&a2,&an,&b1,&b2,&bn))
{
a1++;a2++;b1++;b2++;
flow=an+bn<<;
for(int i=;i<=n;i++)
for(int j=;j<=n;j++)
c[i][j]=getch();
INIT();
while(now<flow && bfs()) now=now+dfs(,flow);
if(now<flow)
{
puts("No");
continue;
}
swap(b1,b2);
INIT();
while(now<flow && bfs()) now=now+dfs(,flow);
if(now<flow)
puts("No");
else
puts("Yes");
}
return ;
}
05-11 17:21
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