Reactor Cooling

无源汇上下界最大流问题。

1、流量平衡。

2、满足上下界

模板题。

#include <iostream>
#include <queue>
#include <vector>
#include <cstdio>
#include <cstring>
using namespace std; const int MAXN = 200000 + 10;
const int INF = 1 << 30;
struct Edge{
int from,to,cap,flow;
Edge(){};
Edge(int _from,int _to,int _cap,int _flow)
:from(_from),to(_to),cap(_cap),flow(_flow){};
}; vector<Edge> edges;
vector<int> G[MAXN];
int d[MAXN],cur[MAXN];
int src,sink,N,M;
bool vst[MAXN]; int b[MAXN],du[MAXN];
int sum; void init(){
src = N + 1; sink = src + 1;
for(int i = 0;i <= sink;++i)
G[i].clear();
edges.clear();
} void addEdge(int from,int to,int cap){
edges.push_back(Edge(from,to,cap,0));
edges.push_back(Edge(to,from,0,0));
int sz = edges.size();
G[from].push_back(sz - 2);
G[to].push_back(sz - 1);
} bool BFS(){
queue<int> Q;
memset(vst,0,sizeof(vst));
Q.push(src);
d[src] = 0;
vst[src] = 1; while(!Q.empty()){
int x = Q.front(); Q.pop();
for(int i = 0;i < G[x].size();++i){
Edge& e = edges[G[x][i]];
if(!vst[e.to] && e.cap > e.flow){
vst[e.to] = 1;
d[e.to] = d[x] + 1;
Q.push(e.to);
}
}
} return vst[sink];
} int DFS(int x,int a){
if(x == sink||a == 0)
return a; int flow = 0,f;
for(int& i = cur[x];i < G[x].size();++i){
Edge& e = edges[G[x][i]];
if(d[e.to] == d[x] + 1 && (f = DFS(e.to,min(a,e.cap - e.flow))) > 0){
e.flow += f;
edges[G[x][i]^1].flow -= f;
flow += f;
a -= f;
if(a == 0) break;
}
}
return flow;
} int maxFlow(){
int flow = 0;
while(BFS()){
memset(cur,0,sizeof(cur));
flow += DFS(src,INF);
}
return flow;
} void solve(){
int flow = maxFlow(); if(flow != sum){
puts("NO");
return;
} puts("YES");
for(int i = 0;i < M;++i){
printf("%d\n",edges[i<<1].flow + b[i]);
}
} int main()
{
// freopen("Input.txt","r",stdin); int T;
scanf("%d",&T);
while(T--){
scanf("%d%d",&N,&M);
init();
int u,v,c;
memset(du,0,sizeof(du));
for(int i = 0;i < M;++i){
scanf("%d%d%d%d",&u,&v,&b[i],&c);
addEdge(u,v,c - b[i]);
du[u] -= b[i];
du[v] += b[i];
}
sum = 0;
for(int i = 1;i <= N;++i){
if(du[i] > 0){
addEdge(src,i,du[i]);
sum += du[i];
}
else
addEdge(i,sink,-du[i]);
} solve();
}
return 0;
}
05-11 11:33