正则表达式比较带有Umlaut和非Umlaut变体的字符串

问题描述

任何人都可以使用JavaScript正则表达式来帮助我，我可以使用它们来比较相同的字符串，并考虑它们的非Umlaut版本.

Can anyone help me with a javascript regular expression that I can use to compare strings that are the same, taking into acccount their non-Umlaut-ed versions.

例如，德语中的Grüße也可以写为 Gruesse .这两个字符串应视为相同.映射(暂时忽略大小写)为:

for example, in German the word Grüße can also be written Gruesse. These two strings are to be considered identical. The mappings (ignoring casings for the moment) are:

• ä= ae
• ü= ue
• ö= oe
• ß= ss

由于没有太多联结"要考虑，我可以为每个变体进行替换，但是我想知道是否有更优雅的方式，尤其是因为将来可能需要扩展此用例以包括例如斯堪的纳维亚字符...

As there are not many "couplets" to consider I could do a replace for each variation, but I'm wondering if there is a more elegant way, especially as this use case might need to be extended in future to include e.g. Scandanavian characters...

推荐答案

类似

tr = {"ä":"ae", "ü":"ue", "ö":"oe", "ß":"ss" }

replaceUmlauts = function(s) {
    return s.replace(/[äöüß]/g, function($0) { return tr[$0] })
}

compare = function(a, b) {
    return replaceUmlauts(a) == replaceUmlauts(b)
}

alert(compare("grüße", "gruesse"))

您可以通过在"tr"中添加更多条目来轻松扩展此范围

you can easily extends this by adding more entries to "tr"

不是很优雅，但是可以工作

not quite elegant, but works

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