在Neo4j中记住和重用先前查询结果的方法

问题描述

我正在使用带有宝石Neography的Neo4j在Ruby中进行编码.查询时，我使用Neography提供的execute_neo4j_query方法.我不确定最佳做法.

I am coding in Ruby using Neo4j with the gem Neography. When doing query, I use the method execute_neo4j_query provided by Neography. I am not sure about the best practice.

假设我使用以下代码来获取用户:

Suppose I use following code to fetch a user:

user1 = @neo.execute_neo4j_query("
      MATCH (user:User {user_id: '#{params[:user_id_1]}'})
      RETURN id(user)
      LIMIT 1
      ")

并类似地获取另一个用户

and to fetch another user similarly

user2 = @neo.execute_neo4j_query("
      MATCH (user:User {user_id: '#{params[:user_id_2]}'})
      RETURN id(user)
      LIMIT 1
      ")

然后我对这两个用户做了一些事情.

Then I did some stuff with this two users.

现在我需要在这两个用户之间创建边缘，所以我做到了

Now I need to create an edge between this two users, so I did this

@neo.execute_neo4j_query("
      MATCH (user1:User {user_id: '#{params[:user_id_2]}'})
      MATCH (user2:User {user_id: '#{params[:user_id_2]}'})
      CREATE UNIQUE (user1)-[:FOLLOW]->(user2)
      ")

但是，我认为这种方法并不是最佳选择，因为我两次询问了相同的两个用户.

However, I believe such approach is not optimal, since I queried for the same two users twice.

我的问题是:

1)是否可以使用Neography重用先前查询的结果?

1) Is there a way to reuse previously queried results using Neography?

2)除了直接使用execute_neo4j_query之外，是否建议使用Neography提供的方法(例如@ neo.create_node)?我选择后者是因为我不确定封装的方法是否可以满足我的任务.因此，如果您可以用本机Neography代码重写我的上述代码，将不胜感激.

2) Is it recommended to use methods provided by Neography such as @neo.create_node other than using execute_neo4j_query directly? I choose the latter because I am not sure if the encapsulated methods can satisfy my task. So, if you can rewrite my above codes in native Neography code, it will be greatly appreciated.

推荐答案

1. 如果您不知道为什么要使用它，请不要再使用开始
2. 使用事务性的密码学中的密码支持
3. 在密码查询中使用参数，例如MATCH (u:User {name:{name}}) RETURN u

1. Don't use start anymore if you don't know why you would use it
2. use the transactional cypher support in neography
3. Use Parameters in your cypher queries, like MATCH (u:User {name:{name}}) RETURN u

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