访问Python列表类型

问题描述

我写了一个包含str数据的代码

I write a code that has str data

def characters(self, content):
    self.contentText = content.split()
# self.contentText is List here

我正在将self.contentText列表发送给另一个模块，如下所示:

I am sending self.contentText list to another module as:

self.contentText = Formatter.formatter(self.contentText)

在这种方法中，我正在编写以下代码:

In this method, I am writing below code:

remArticles = remArticles = {' a ':'', ' the ':'', ' and ':'', ' an ':'', '&  nbsp;':''}

for i in remArticles:
  print type(contentText) 
  print "1"
  contentText = contentText.replace(i, remArticles[i])
  print type(contentText) 

我收到错误消息:

contentText = contentText.replace(i, remArticles[i])
AttributeError: 'list' object has no attribute 'replace'

如果我将其更改为:

for i in remArticles:
  contentText = contentText.pop(i)

我遇到以下错误:

contentText = contentText.pop(i)#replace(i, remArticles[i])
AttributeError: 'str' object has no attribute 'pop'

推荐答案

contextText确实是一个列表，因此没有replace方法.第二个错误是由以下事实引起的:您用返回值contextText.pop(i)覆盖了contextText(返回弹出的值)，因此在循环contextText的第一次迭代之后不再是列表而是字符串

contextText is indeed a list and as such has no replace method. The second error is caused by the fact that you overwrite contextText with the return value of contextText.pop(i) (which returns the popped value), so that after the first iteration of the loop contextText is no longer a list but a string.

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