本文介绍了如何在swift中将double转换为字节数组?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我知道如何在java中做到这一点(参见),但是我找不到java的ByteBuffer的快速等价物,因此找不到它的.putDouble(double value)方法。
I know how to do it in java (see here), but I couldn't find a swift equivalent for java's ByteBuffer, and consequently its .putDouble(double value) method.
func doubleToByteArray(value: Double) -> [UInt8]? {
. . .
}
doubleToByteArray(1729.1729) // should return [64, 155, 4, 177, 12, 178, 149, 234]
推荐答案
typealias Byte = UInt8
func toByteArray<T>(var value: T) -> [Byte] {
return withUnsafePointer(&value) {
Array(UnsafeBufferPointer(start: UnsafePointer<Byte>($0), count: sizeof(T)))
}
}
toByteArray(1729.1729)
toByteArray(1729.1729 as Float)
toByteArray(1729)
toByteArray(-1729)
但结果与您的预期相反(因为字节顺序):
But the results are reversed from your expectations (because of endianness):
[234, 149, 178, 12, 177, 4, 155, 64]
[136, 37, 216, 68]
[193, 6, 0, 0, 0, 0, 0, 0]
[63, 249, 255, 255, 255, 255, 255, 255]
已添加:
Added:
func fromByteArray<T>(value: [Byte], _: T.Type) -> T {
return value.withUnsafeBufferPointer {
return UnsafePointer<T>($0.baseAddress).memory
}
}
let a: Double = 1729.1729
let b = toByteArray(a) // -> [234, 149, 178, 12, 177, 4, 155, 64]
let c = fromByteArray(b, Double.self) // -> 1729.1729
对于Xcode8 / Swift3.0:
For Xcode8/Swift3.0:
func toByteArray<T>(_ value: T) -> [UInt8] {
var value = value
return withUnsafePointer(to: &value) {
$0.withMemoryRebound(to: UInt8.self, capacity: MemoryLayout<T>.size) {
Array(UnsafeBufferPointer(start: $0, count: MemoryLayout<T>.size))
}
}
}
func fromByteArray<T>(_ value: [UInt8], _: T.Type) -> T {
return value.withUnsafeBufferPointer {
$0.baseAddress!.withMemoryRebound(to: T.self, capacity: 1) {
$0.pointee
}
}
}
对于Xcode8.1 / Swift3.0.1
For Xcode8.1/Swift3.0.1
func toByteArray<T>(_ value: T) -> [UInt8] {
var value = value
return withUnsafeBytes(of: &value) { Array($0) }
}
func fromByteArray<T>(_ value: [UInt8], _: T.Type) -> T {
return value.withUnsafeBytes {
$0.baseAddress!.load(as: T.self)
}
}
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